If 28.0 grams of a gas occupies 22.4 liters at STP, the gas could be carbon monoxide, CO
<h3>Ideal gas </h3>
We understood from the ideal gas equation that 1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP)
<h3>How to determine the identity of the gas</h3>
To determine the identity of the gas, we shall determine the mass of 1 mole of each gas. This can be obtained as
For C₂H₂
1 mole of C₂H₂ = (12×2) + (2×1) = 26 g
For C₂H₆
1 mole of C₂H₆ = (12×2) + (6×1) = 30 g
For CO₂
1 mole of CO₂ = 12 + (16×2) = 44 g
For CO
I mole of CO = 12 + 16 = 28 g
From the above illustrations, we can see that 1 mole of CO is equivalent to 28 g.
Thus, the correct answer to the question is CO
Learn more about ideal gas equation:
brainly.com/question/4147359
#SPJ1
Answer:
972 ppm
Explanation:
Percent (parts per hundred - pph), parts per million & parts per billion are ratios of a component of interest divided by total mix of several components.
That is, given 28%, this says 28/100, or 28ppm says 28/10⁶, or 28ppb says 28/10⁹.
To convert from the given (=> any of the three concentration ratios) simply multiply (X) where you wish to go.
Examples:
- Convert 35% to ppm and ppb
- 35% = (35/100) x 10⁶ppm = 3.5 x 10⁵ ppm
- _______________________________
- Convert 43 ppm to %
- 43 ppm = (43/10⁶) x 100% = 4.3 x 10³%
- ______________________________
- Convert 81 ppb to ppm
- 81 ppb = (81/10⁹) x 10⁶ppm = 8.1 x 10⁻² ppm
Notice how each 'Given' is expressed as a ratio of amount/100 (given pph or %), or amount/10⁶ (given ppm) or amount/10⁹ (given ppb). All you need to do here is multiply by where you want to go.
=> Given % = (amount/100) x 10⁶ => ppm
=> Given ppm = (amount/10⁶) x 100 => %, or pph
=> Given ppb = (amount/10⁹) x 10⁶ => ppm
Given ratio x 100 = %, or x 10⁶ => ppm or x 10⁹ => ppb
Your Problem:
Given = (0.0972g/100g) x 10⁶ppm = 972 ppm
or, if you wish ppb => (0.0972g/100g) x 10⁹ppb = 972,000 ppb
Answer:
the reaction is exothermic
Explanation:
heat will be produced from the reaction
