Answer:
28/9
Step-by-step explanation:
If the roots are J and K, then:
3 (x − J) (x − K) = 0
3 (x² − (J+K)x + JK) = 0
So if we factor out the leading coefficient:
3x² − 2x − 4 = 0
3(x² − 2/3x − 4/3) = 0
The coefficient of the second term is the sum of the roots:
J + K = 2/3
And the constant is the product of the roots:
JK = -4/3
If we take the sum of the roots and square it:
(J + K)² = (2/3)²
J² + 2JK + K² = 4/9
And subtract twice the product:
J² + K² = 4/9 − 2JK
J² + K² = 4/9 − 2(-4/3)
J² + K² = 4/9 + 8/3
J² + k² = 28/9
Answer:
the first one
Step-by-step explanation:
y-y1=m(x-x1)
y-20=12(x-3)

simplify:

Answer:
0
Step-by-step explanation:
Try looking at it in 2 ways- left side and right side. On the left side we have -4*5, which equals -20. On the right we have -4-20, which equals -24. so then when we add it all together (not literally) we get -20=-24. Since -20 and -24 obviously do not equal eachother, there is no solution.
Answer:
let the number be 'x'
now,
so, the number is 6.
hope it helps
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