Distance = Average speed * Time = 48*10 = 480 miles
So, they drove for 480 miles
<u>Given</u>:
The base of each triangular base is 42 m.
The height of each triangular base is 20 m.
The sides of the triangle are 29 m each.
The height of the triangular prism is 16 m.
We need to determine the surface area of the triangular prism.
<u>Surface area of the triangular prism:</u>
The surface area of the triangular prism can be determined using the formula,
where b is the base of the triangle,
h is the height of the triangle,
s₁, s₂ and s₃ are sides of the triangle and
H is the height of the prism.
Substituting the values, we get;
Thus, the surface area of the triangular prism is 2440 m²
First, find the gradient/slope:
Use slope formula:
m=(y2-y1)/(x2-x1)
=(11-5)/(3-1)
=6/2
=3
Then use the line equation formula:
y=mx+c
You can substitute (1,5) if you like, also must substitute the slope as well!
5=3x1+c
c=2
Then find the full equation, which gives you the answer:
y=3x+2
Answer:
144 children and 170 adults
Step-by-step explanation:
make 2 equations
make :
the children as the regarded as the variable : x
the adults are the regarded as the variable : y
<em>5x + 6 y = 1740</em>
<em>x + y = 314</em>
<h3><u>solve this by the method of elimination </u></h3>
5x + 6y = 1740
5(x + y = 314)
= 5x + 5y = 1570
5x + 6y = 1740
5x + 5y = 1570
the 5x is cancelled out
6y - 5y = 1740 - 1570
y = 170
now replace the value of y in the eqaution
5x + 6 (170) = 1740
5x =720
x = 144
hence they were 144 children and 170 adults
mark as brainiest
Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1
