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AlekseyPX
3 years ago
10

A department store purchases logo shirts at a cost of $10 per shirt. They increase the price 100% and put them on the sales floo

r. Every month that a shirt doesn’t sell, the store reduces the selling price by 25%. After three monthly reductions, the final shirt from the shipment is sold. There is a 5% sales tax on the selling price. Explain the steps for finding the final cost to the customer for that shirt?
Mathematics
2 answers:
Andrei [34K]3 years ago
7 0

The original selling price is found by multiplying 100% by $10 and adding that to the original $10. The logo shirt goes on the sale floor for $20. Each of the next three months, the reduced price is found by multiplying the current sale price by 75%. The tax is found by multiplying 5% by the final discounted price and adding the tax to the final sale price.

Irina-Kira [14]3 years ago
5 0

Answer:

Sample response: The original selling price is found by multiplying 100% by $10 and adding that to the original $10. The logo shirt goes on the sale floor for $20. Each of the next three months, the reduced price is found by multiplying the current sale price by 75%. The tax is found by multiplying 5% by the final discounted price and adding the tax to the final sale price.

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today's local newspaper lists 20 stocks of local interest. of those stocks ten increased five decreased and five remained unchan
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Answer:

P(x=2) = 0.2368

Step-by-step explanation:

given data

stocks of local interest N = 20

stocks increased K = 10

stocks decreased =  5

remained unchanged = 5

solution

we take here no of stock that are increased randomly n = 2

so here Hypergeometric random variable can take integer value

{max(0, n+k - N ), min(n,K) } = {0,2}

so here

P(x=2)

so

P(x=k)  = \frac{(^K_k)\times (^{N-K}_{n-k}) }{(^N_n)}      .......................1

P(x=2 ) = \frac{(^{10}_2)\times (^{20-10}_{2-2}) }{(^{20}_2)}    

solve it we get

P(x=2 ) = 0.236842

now we use excel function as

HYPGEOM.DIST (k,n,N.cumulative)   .....................2

so it will be

HYPGEOM.DIST (2,2,10,,false)

we get

HYPGEOM.DIST (2,2,10,,false)  = 0.236842

so

P(x=2) = 0.2368

4 0
4 years ago
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MissTica
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3 0
4 years ago
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3 years ago
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ycow [4]

Answer:

About\ 193 \frac{209}{372} \ tons\ of \ steel

Step-by-step explanation:

Given the amount of tons of steel produced monthly by a factory to be 6000 5/12 tons, to determine their daily production, we need to use the conversion;

Maximum of 31 days = 1 month

This means that the steel company produces 6000 5/12 tons of steel in 31 days.

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in a day, the company will therefore produce approx. (72,005/12)/31 tons of steel.

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= 193  209/372 tons of steel.

Hence, the factory produces about 193 \frac{209}{372} tons of steel daily

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