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kondor19780726 [428]
3 years ago
5

A material that lets electricity pass through it is called​

Physics
1 answer:
ZanzabumX [31]3 years ago
6 0

These metals are called electrical (conductors)

5 star plz and brainliest

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When a weather map shows a wind symbol at 270 it indicates that the wind is coming from the?
Montano1993 [528]
For the answer to the question above, <span>When a weather map shows a wind symbol at 270 it indicates that the wind is coming from the WEST.
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
5 0
3 years ago
If an elevator is moving at a speed of 5 m/s and the person in it is 82 kg what is the person’s kinetic energy?
dalvyx [7]

Answer:

KE 1025J

\frac{1}{2} m {v}^{2}  \\

Explanation:

\frac{1}{2}  \times 82 \times  {5}^{2}

1025J

6 0
3 years ago
A space station with a radius of 120 m rotates once every 70 s to create artificial gravity. If the astronaut has an earth weigh
Alina [70]

Answer:

Artificial weight = 70.27 N = 15.80 lbs

Explanation:

The earth weight of the astronaut = 160 lbs = 711.72 N

The weight on earth = m × g(earth)

g(earth) = 9.8 m/s²

711.72 = m × 9.8

m = (711.72/9.8)

m = 72.62 kg

But at the space station, the space station rotates once every 70 s to create an artificial radial acceleration that creates a radial gravity pulling the objects on the space station towards the centre of that space station.

radial acceleration = α = (v²/r)

v = rw,

α = (rw)²/r

α = rw²

r = radius of rotation = 120 m

w = angular velocity = (2π/70) (it completes 1 rotation, 2π radians, in 70 s)

w = 0.0898 rad/s

α = 120 × (0.0898²)

α = 0.968 m/s²

Artificial weight = (mass of astronaut) × (Radial acceleration) = 72.62 × 0.968

Artificial weight = 70.27 N = 15.80 lbs

Hope this Helps!!!

5 0
4 years ago
A potential energy function for a system in which a two-dimensional force acts is of the form U = 3x6y − 5x. Find the force that
liq [111]

Answer:

Force, F=((-18x^5y+5)i+(-3x^6)j)\ N

Explanation:

Given that,

A potential energy function for a system in which a two-dimensional force acts is of the form of :

U=3x^6y-5x

We need to find the force that acts at the point (x, y). The force in 2 dimensional with components is given by :

F=(\dfrac{-dU}{dx},\dfrac{-dU}{dy})\\\\F=(\dfrac{-d(3x^6y-5x)}{dx},\dfrac{d(3x^6y-5x)}{dy})\\\\F=(-(18x^5y-5)),(-(3x^6))\\\\F=((-18x^5y+5)i+(-3x^6)j)\ N

So, the force acting at the point (x,y) is ((-18x^5y+5)i+(-3x^6)j)\ N. Hence, this is the required solution.

7 0
3 years ago
A stargazer has an astronomical telescope with an objective whose focal length is 195 cm and an eyepiece whose focal length is 1
Colt1911 [192]

Answer:

The best angular magnification is

-375

Explanation:

Fe = Fo - L

From the question, (Fo) = 1.08 cm while (L) = 0.56cm

Thus, Fe = 1.08 - 0.56 = 0.52cm

Now, let's apply the angular magnification equation ;

M = - Di/Do

Where Di is the distance from the lens to the image and Do is the distance of the object to the lens.

In this question, Di is represented by f which is the distance from the lens to the image and it is f= 195cm

Also,Do is represented by Fe which is 0.52cm and it is the distance of the object to the lens.

Thus m = - f/fe = - 195/0.52 = - 375

6 0
4 years ago
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