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siniylev [52]
3 years ago
5

In certain cases, using both the momentum principle and energy principle to analyze a system is useful, as they each can reveal

different information. You will use the both momentum principle and the energy principle in this problem. A satellite of mass 2500 kg orbits the Earth in a circular orbit of radius of 8.9 106 m (this is above the Earth's atmosphere).The mass of the Earth is 6.0 1024 kg. What is the magnitude of the gravitational force on the satellite due to the earth
Physics
1 answer:
kramer3 years ago
8 0

Explanation:

The gravitational force equation is the following:

F_G = G * \frac{m_1 m_2}{r^2} \\

Where:

G = Gravitational constant = 6.67408 * 10^{-11} m^3 kg^{-1} s^{-2}

m1 & m2 = the mass of two related objects

r = distance between the two related objects

The problem gives you everything you need to plug into the formula, except for the gravitational constant. Let me know if you need further clarification.

You might be interested in
A construction worker uses 1,000 J of work to screw two boards together. The screw does 855 J of work. Calculate the efficiency
Dovator [93]

Answer:

The efficiency of the screw is 85.5%

Explanation:

to calculate efficiency you have to do

efficiency=energy output/ energy input × 100%

so e=855/1000 × 100%=85.5%

7 0
2 years ago
How can I solve the following?
skad [1K]

Answer:

Part A - 4.084 mJ

Part B - 0.908 mJ

Part C - 8.168 mJ

Explanation:

Part A: How much energy is stored in the capacitor network as shown in (Figure 1)?

Since capacitors C₂ and C₃ are in series, their equivalent capacitance is C',

1/C' = 1/C₂ + 1/C₃      (Since C₁ = C₂ = C₃ = C)

1/C' = 1/C + 1/C

1/C' = 2/C

C' = C/2

Since C' is in parallel with C₁, the equivalent capacitance for the circuit is C" = C₁ + C' = C + C/2 = 3C/2

C" = 3C/2

The energy stored in the circuit, W = 1/2C"V² where C" = equivalent capacitance = 3C/2 and V = voltage = 15.0 V

W = 1/2C"V²

W = 1/2(3C/2)V²

W = 3CV²/4

since C = 24.2 μF = 24.2 × 10⁻⁶ F

W = 3CV²/4

W = 3 × 24.2 × 10⁻⁶ F (15.0 V)²/4

W = 3 × 24.2 × 10⁻⁶ F × 225 V²/4

W = 16335/4 × 10⁻⁶ FV²

W = 4083.75 × 10⁻⁶ J

W = 4.08375 × 10⁻³ J

W = 4.08375 mJ

W ≅ 4.084 mJ

Part B: How much energy would be stored in the capacitor network if the capacitors were all in series?

If the capacitors are connected in series, their equivalent resistance is C'

and 1/C' = 1/C₁ + 1/C₂ + 1/C₃

Since C₁ = C₂ = C₃ = C

1/C' = 1/C + 1/C + 1/C

1/C' = 3/C

C' = C/3

The energy stored in the circuit, W = 1/2C'V² where C' = equivalent capacitance = C/3 and V = voltage = 15.0 V

W = 1/2C'V²

W = 1/2(C/3)V²

W = CV²/6

since C = 24.2 μF = 24.2 × 10⁻⁶ F

W = CV²/6

W = 24.2 × 10⁻⁶ F (15.0 V)²/6

W = 24.2 × 10⁻⁶ F × 225 V²/6

W = 5445/6 × 10⁻⁶ FV²

W = 907.5 × 10⁻⁶ J

W = 0.9075 × 10⁻³ J

W = 0.9075 mJ

W ≅ 0.908 mJ

Part C: How much energy would be stored in the capacitor network if the capacitors were all in parallel?

If the capacitors are connected in parallel, their equivalent resistance is C'

and C' = C₁ + C₂ + C₃

Since C₁ = C₂ = C₃ = C

C' = C + C + C

C' = 3C

The energy stored in the capacitor network, W = 1/2C'V² where C' = equivalent capacitance = 3C and V = voltage = 15.0 V

W = 1/2C'V²

W = 1/2(3C)V²

W = 3CV²/2

since C = 24.2 μF = 24.2 × 10⁻⁶ F

W = 3CV²/2

W = 3 × 24.2 × 10⁻⁶ F (15.0 V)²/2

W = 3 × 24.2 × 10⁻⁶ F × 225 V²/2

W = 16335/2 × 10⁻⁶ FV²

W = 8167.5 × 10⁻⁶ J

W = 8.1675 × 10⁻³ J

W = 8.1675 mJ

W ≅ 8.168 mJ

5 0
2 years ago
How long would it take to walk 10000 miles?
SpyIntel [72]
Well if you take 10 minutes to walk each mile and you don't stop by continuously walking... it would take approximately 69 and a half daysSource(s):<span>10 minutes x 10,000 miles= 100,000 minutes 
100,000 minutes/ 60 minutes (1 hour)= 1,666.66667 hours 

1,666.66667 hours/ 24 hours (1 day)= 69.4444446 days 
69.4444446 days rounds to 69.5 days which means that would be about 2 months and a week.</span>
6 0
3 years ago
Why is tungsten used as a filament in a bulb?
Viktor [21]

Answer:

because of tungsten's high melting point

Explanation:

7 0
3 years ago
Which has more momentum, a small object moving 10 miles per hours or a large object at rest?
xeze [42]
Well the object will have no Momentum since it is not moving, so a small object that is going 10 mph will have Momentum.
3 0
3 years ago
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