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In-s [12.5K]
3 years ago
15

40 is how many times less than 400

Mathematics
2 answers:
lisov135 [29]3 years ago
6 0
400/40 = 10
..............
Akimi4 [234]3 years ago
6 0
40 is 10 times less than 400. to find this you divide 400 by 40
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What describes the geometric construction
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To draw a shape, line or angle accurately using a compass and straightedge (ruler).
4 0
3 years ago
Help pls I'll give 25 points
RideAnS [48]

Answer:

\text{C. }60

Step-by-step explanation:

<u>Question from image</u>:

"The digits 1, 2, 3, 4, and 5 can be formed to arrange 120 different numbers. How many of these numbers will have the digits 1 and 2 in increasing order? For example, 14352 and 51234 are two such numbers."

Let's start by taking a look with the number 1. There are four possible places 1 could be, because there needs to be space for the 2 after it.

Checkmarks mark where the 1 can be, the <em>x</em> marks where it cannot be.

\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{X}

Let's start with the first position:

\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are four places the 2 can be. For each of these four places, we can arrange the remaining 3 digits in 3!=6 ways. Therefore, there are 4\cdot 6=\boxed{24} possible numbers when 1 is the first digit of the number.

Continue this process with the remaining possible positions for 1.

Second position:

\underline{X}\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are three places the 2 can be, since the 2 must be behind the 1. For each of these three places, the remaining 3 digits can be arranged in 3!=6 ways. Therefore, there are 3\cdot 6=\boxed{18} possible numbers when 1 is the second digit of the number.

The pattern continues. Next there will be 2 places to place the 2. For each of these, there are 3!=6 ways to rearrange the remaining 3 digits for a total of 2\cdot 6=\boxed{12} possible numbers when 1 is the third digit of the number.

Lastly, when 1 is the fourth digit of the number, there is only 1 place the 2 can be. For this one place, there are still 3!=6 ways to rearrange the remaining three numbers. Therefore, there are 1\cdot 6=\boxed{6} possible numbers when 1 is the fourth digit of the number.

Thus, there are 24+18+12+6=\boxed{60} numbers that will have the digits 1 and 2 in increasing order, from a set of 120 five-digit numbers created by the digits 1 through 5, where no digit may be repeated.

5 0
2 years ago
Find the angle measure and round to the nearest Tenth.<br><br> cos0 = 7/10<br><br> x = ? degrees
Ad libitum [116K]
I believe it is 45.6
5 0
3 years ago
If a rectangle has side lengths 5x-y and x+4y what would be the area and perimeter of the rectangle?
Dafna1 [17]

Answer:

<em>Answer is</em><em> </em><em>given</em><em> </em><em>below with explanations</em><em>. </em>

Step-by-step explanation:

given \:  \: l = 5x - y \: and \: \:  b = x + 4y \\ area \: of \: rectangle \:= l \times b \: sq.units \\  = (5x - y)(x + 4y) \\  = 5 {x}^{2}  + 20xy - xy - 4 {y}^{2}  \\  = 5 {x}^{2}  + 19xy - 4 {y}^{2}  \\ perimeter \: of \: rectangle \\  = 2(l + b) \\  = 2(5x - y + x + 4y) \\  = 2(6x + 3y) \\  = 12x + 6y

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

6 0
3 years ago
What is an equation of the line that is perpendicular to y=−23x+5 and passes through the point (2, 11) ?
hichkok12 [17]

Answer:

The equation would be y = 1/23x - 251/23

Step-by-step explanation:

To start, you need to locate the slope of the first equation. Since the slope is the coefficient of x, we know it to be -23. Now, the perpendicular slope is the opposite and reciprocal of that, which makes the new slope 1/23.

Now that we have this, we can use the point and the slope in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 11 = 1/23(x - 2)

y - 11 = 1/23x - 2/23

y = 1/23x - 251/23

5 0
3 years ago
Read 2 more answers
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