Question

Which of the following is the height of the special trapezoid if WX=16 , YZ=16 and the area is 80 units 2?

Answer 1

The answer is 5 bc 80/16=5

Answer 2

Answer:

The height of trapezoid WXYZ is 5 units.

Step-by-step explanation:

Given : A  trapezoid WXYZ having  WX=16 , YZ=16 and the area is 80 units²

We have to find the height of  trapezoid WXYZ

W know area of trapezoid is $\frac{1}{2}\times \text{(sum of parallel sides)} \times \text{height}$

Given area is 80 units²

Two parallel sides are WX=16 , YZ=16

Thus sum of parallel sides is 16 + 16 = 32 units

Let height = h unit

Substitute , we get,

$80=\frac{1}{2} \times 32 \times h$

Solving for h , we have

$80=16 \times h$

Divide both side by 16, we have

h = 5

Thus, the height of trapezoid WXYZ is 5 units.