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lana66690 [7]
3 years ago
9

Use the algebraic steps to find the equation you would use to solve for bA=bh/2

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
4 0
Your job is to isolate b. First I would try to get h and 2 on the other side.

You can do this by multiplying both sides by 2. Now the equation reads A*2=bh

Then you can move h by dividing both sides by h. Now it will say A*2/h=b.

There you go. Your equation to solve for b is b=A*2/h.
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What is the expression and answer
swat32

Answer:

Step-by-step explanation:

<em>L</em> is 2* <em>W</em> so L=2W

perimeter= 2w+2l

plug in whats given to get

perimeter=2w+4w   4w is because L is *2 of W so that makes L=2w

36=6w

36/6=6

6w/6=w

w=6

6*2=12=L

now we have 6*12=72=Area

3 0
3 years ago
Find ​(a) the slope of the curve at the given point​ p, and ​(b) an equation of the tangent line at p. y=−2−9x2​; ​p(2​,−38​)
Neporo4naja [7]

Answer:

a) -36

b) y = -36x +34

Step-by-step explanation:

a) The slope is found using the derivative of the function.

  f'(x) = dy/dx = 0 -9(2x) = -18x

Then at x=2, the slope is ...

  f'(2) = -18·2 = -36

___

b) The point-slope form of the equation can be written as ...

  y = -36(x -2) -38

Simplifying to slope-intercept form, we get ...

  y = -36x +34

6 0
3 years ago
Use a known maclaurin series to obtain the maclaurin series for the given function. f(x = 8x2 tan?1(7x3
11Alexandr11 [23.1K]
Going out on a limb here and guessing that the function is

f(x)=8x^2\tan^{-1}(7x^3)

Please correct me if this isn't the case.

Recall that

\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^nx^{2n+1}}{2n+1}

which converges for |x|.

It follows that

8x^2\tan^{-1}(7x^3)=8x^2\displaystyle\sum_{n\ge0}\frac{(-1)^n(7x^3)^{2n+1}}{2n+1}
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6 0
4 years ago
Pls help mark u brainlist
Molodets [167]
Do what that person with the long explanation says it’s most likely right!!
8 0
3 years ago
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nalin [4]

Answer:

A.) The coordinates of M' are (-2/4, -4/5)

The coordinates of N' are (1/5, 1)

B.) The scale factor of the dialation is 3

7 0
3 years ago
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