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hodyreva [135]
2 years ago
11

The original programs awaiting tanslation is called​

Computers and Technology
1 answer:
-Dominant- [34]2 years ago
7 0

Answer:

I think it's called a source program

Explanation:

A translator or programming language processor is a generic term that can refer to anything that converts code from one computer language into another.

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If I Uninstall Nba 2k 19 from my ps4 will my career be gone forever?​
Rudik [331]

Answer:

Not unless you have a ps plus membership

Explanation:

Ps plus have cloud storage so if you have ps plus membership,even if you delete 2k19 your data will be saved in the cloud storage therefore your my carrer will not be gone forever!

7 0
3 years ago
Read 2 more answers
A_________is a way for students to keep track of information during research.
Fudgin [204]
Note pad your welcome


4 0
3 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
In this lab, you complete a C++ program that swaps values stored in three int variables and determines maximum and minimum value
Sergio039 [100]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

int first = 0,second = 0,third = 0;//defining integer variable  

int temp; //defining integer variable

const string SENTINEL = "done"; // defining a string variable as constant  

string repeat;// defining a string variable  

bool notDone = true; //defining bool variable

cout << "Enter first number: ";//print message

cin >> first;//input value

cout << "Enter second number: ";//print message

cin >> second;//input value

cout << "Enter third number: ";//print message

cin >> third;//input value

while(notDone == true)//defining a loop to check the value  

{

if(first > second)//use if to compare first and second value

{

int temp = first;//defining temp to hold first value

first = second;//holding second value in first variable

second = temp;//holding temp value in second variable

}

if(second > third)//use if to compare second and third value

{

int temp = second;//defining temp to hold second value

second = third;//holding second value in third variable

third = temp;//holding temp value in third variable

}

cout << "Smallest: " << first << endl;//print smallest value

cout << "Next smallest: " << second << endl;//print Next smallest value

cout << "Largest: " << third << endl;////print Largest value

cout << "Enter any letter to continue or done to quit: ";//print message

cin >> repeat;//holding string value

if (repeat == SENTINEL)

{

notDone = false;//holding bool value

}  

else //else block

{

cout << "Enter first number: ";//print message

cin >> first;//input value

cout << "Enter second number: ";//print message

cin >> second;//input value

cout << "Enter third number: ";//print message

cin >> third;//input value

}

return 0;

}

}

Output:

Please find the attached file.

Explanation:

  • Inside the main method Four integer variable "first, second, third, and temp" is declared in which first three variable is used for input value and temp is used to compare value.
  • In thew next step, two string variable "SENTINEL and repeat" is declared in which "SENTINEL" is constant and a bool variable "notDone" is declared.
  • After input the value from the user-end a loop is declared that compare and swap value and print its value.

6 0
3 years ago
What can multivariable calculus show for a data set.
dalvyx [7]

Answer:

They can help to explain the relationship between the output and input variables.

Hope this Helps!

5 0
3 years ago
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