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Rom4ik [11]
3 years ago
5

A cylindrical specimen of a metal alloy 48.8 mm long and 9.09 mm in diameter is stressed in tension. A true stress of 327 MPa ca

uses the specimen to plastically elongate to a length of 55.0 mm. If it is known that the strain-hardening exponent for this alloy is 0.3, calculate the true stress (in MPa) necessary to plastically elongate a specimen of this same material from a length of 48.8 mm to a length of 57.6 mm

Engineering
1 answer:
Gnom [1K]3 years ago
5 0

Answer:

The true stress necessary to plastically elongate the specimen is 406.69MPa

Explanation:

The Explanation or Solving is on the attached document.

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An inventor claims to have developed a food freezer that at steady state requires a power input of 0.25 kW to extract energy by
Snowcat [4.5K]

Answer:

The claim is false. (COP_{real} > COP_{ideal}).

Explanation:

The real coefficient of performance of the food freezer is:

COP_{real} = \frac{\dot Q_{L}}{\dot W}

COP_{real} = \frac{3\,kW}{0.25\,kW}

COP_{real} = 12

The ideal coefficient of performance, that is, when freezer has a reversible process, is:

COP_{ideal} = \frac{T_{L}}{T_{H}-T_{L}}

COP_{ideal} = \frac{270\,K}{293\,K-270\,K}

COP_{ideal} = 11.739

A real freezer has a coefficient of performance lesser than or equal to ideal coefficient of performance. Since supposed real coefficient of performance is greater than ideal coefficient of performance. The claim is proved to be false.

7 0
4 years ago
100 cubic meters of carbon dioxide initially at 150 C and 50bar is to be isothermally compressed in a frictionless piston and cy
Allushta [10]

Answer:

Explanation:

Given V1 = 100m3

P1 = 50bar

P2 = 300bar

T1 = 150°C = 150°C + 273 = 423k

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Plugging in the values given to get the mass of the carbon dioxide, the detailed steps and appropriate calculation is as shown in the attached file.

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3 years ago
Assignment Using Perman's equation, estimate the potential evapotranspiration for the month of August in locality with the follo
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Answer:

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Explanation:

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3 years ago
Interlocking stacked material is done by​ _____.
Dmitry [639]

Answer:

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Explanation:

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3 years ago
Read 2 more answers
: The interior wall of a furnace is maintained at a temperature of 900 0C. The wall is 60 cm thick, 1 m wide, 1.5 m broad of mat
Snowcat [4.5K]

Answer:

<em>Heat is lost at the rate of 750 J/s or W</em>

<em>The thermal resistance is 1 K/W</em>

Explanation:

interior temperature T_{2} = 900 °C

wall thickness t = 60 cm = 0.6 m

width = 1 m

breadth = 1.5 m

thermal conductivity k = 0.4 W/m-K

outside temperature T_{1} = 150 °C

heat through the wall = ?

The area of the wall A = w x b = 1 x 1.5 = 1.5 m^2

Temperature difference dt = T_{2} - T_{1} = 900 - 150 = 750 °C

note that dt is also equal to 750 K since to convert from °C to K we'll have to add 273 to both temperature, which will still cancel out when we subtract the two temperatures.

To get the heat that escapes through the wall, we use the equation

Q = Ak\frac{dt}{t}

substituting values, we have

Q = 1.5 x 0.4 x \frac{750}{0.6} = <em>750 J/s or W</em>

Thermal resistance R_{t} = \frac{dt}{Q}

R_{t} = 750/750 =<em> 1 K/W</em>

7 0
3 years ago
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