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galina1969 [7]
3 years ago
6

Assignment Using Perman's equation, estimate the potential evapotranspiration for the month of August in locality with the follo

wing data
latitude 20 degrees north
Elevation 200m
• Mean monthly temperature 20 degreeso
• Mean relative humidity: 75%
• Mean sunshine hour= 9hrs
Wind at 2 m height equal 85 km per day
nature of surface cover =green grass​
Engineering
1 answer:
Korolek [52]3 years ago
3 0

Answer:

what do you need help with

Explanation:

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A spherical, stainless steel (k 16 W m1 K-1) tank has a wall thickness of 0.2 cm and an inside diameter of 10 cm. The inside sur
SOVA2 [1]

Answer:

the rate of heat loss is 2.037152 W

Explanation:

Given data

stainless steel K = 16 W m^{-1}K^{-1}

diameter (d1) = 10 cm

so radius (r1)  = 10 /2 = 5 cm = 5 × 10^{-2}

radius (r2)  = 0.2 + 5 = 5.2 cm = 5.2 × 10^{-2}

temperature = 25°C

surface heat transfer coefficient = 6 6 W m^{-2}K^{-1}

outside air temperature = 15°C

To find out

the rate of heat loss

Solution

we know current is pass in series from temperature = 25°C to  15°C

first pass through through resistance R1  i.e.

R1  = ( r2 -  r1 ) / 4\pi  × r1 × r2 × K

R1  = ( 5.2 - 5 ) 10^{-2}  / 4\pi  × 5 × 5.2 × 16 × 10^{-4}

R1  = 3.825 ×  10^{-3}

same like we calculate for resistance R2 we know   i.e.

R2 = 1 / ( h × area )

here area = 4 \pi r2²

area = 4 \pi (5.2 × 10^{-2})²  =  0.033979

so R2 = 1 / ( h × area ) = 1 / ( 6 × 0.033979  )

R2 = 4.90499

now we calculate the heat flex rate by the initial and final temp and R1 and R2

i.e.

heat loss = T1 -T2 / R1 + R2

heat loss = 25 -15 / 3.825 ×  10^{-3} + 4.90499

heat loss =  2.037152 W

8 0
3 years ago
Explain and show work:
belka [17]

Answer:

  5

Explanation:

The sum of the digits of the number is ...

  (4+1+3)+(4+6+5)+(7+8+9) = 8+15+24 = 47

The sum of those digits is 4+7=11, and those digits sum to 1+1 = 2.

That is, the value of the number mod 9 (or 3) is 2.

The ones digit is odd, so the value of the number mod 2 is 1.

This combination of modulo values tells you the mod 6 result is 5.

_____

<em>Additional comment</em>

We can look at the (mod2, mod3) values of the numbers 0 to 5:

  0 ⇒ (0, 0)

  1 ⇒ (1, 1)

  2 ⇒ (0, 2)

  3 ⇒ (1, 0)

  4 ⇒ (0, 1)

  5 ⇒ (1, 2) . . . . the mod {2, 3} results we have for the number of interest.

This process of adding up the digits repeatedly is referred to as "casting out 9s." The result of it is the modulo 9 value of the number (with 0 mapped to 9). Checking the mod 9 result of arithmetic operations is one quick way to spot certain kinds of errors. It can also be used as part of a divisibility test for 3 or 9.

3 0
3 years ago
I can’t find the code
Ymorist [56]

Answer:

what code for

Explanation:

8 0
4 years ago
YO CUTIE! HELP MEEEEEE! Hazardous waste is a category that includes all of the following EXCEPT
madam [21]

your answer should be <u>B. Soluble</u>

3 0
3 years ago
Read 2 more answers
The flowrate through a rectangular channel is 20 cfs. The upstream width of the channel is 10 ft, and the depth of the water in
Liula [17]

To solve this problem we will use the Froude number that relates the Forces of Inertia with the Forces of Gravity. There will be jump in the downstream only if Froude Number (Fr) is greater than 1 at upstream. Our values are given as,

Q = 20cfs\\w= 10ft\\D= 1ft

Then the velocity would be:

V = \frac{Q}{wD}V = \frac{20}{10*1}V = 2ft/s

The number of Froude is given as,

Fr = \frac{V}{gD}^{1/2}

Where,

V = Velocity

g = Gravity

D = Diameter

Replacing we have that

Fr = \frac{2}{32.2}^{1/2}\\Fr = 0.352\\Fr

There will be no Jump, correct answer is B.

5 0
3 years ago
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