<span>The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers.
1st: 2x
2nd: 2x+2
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EQUATION:
2x =(1/2)(2x+2)+10
2x = x + 11
x = 11
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1st: 2x = 22
2nd: 2x + 2 = 24
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2) The greater of two consecutive even integers is 6 less than the times the lesser
</span><span>3) Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91.
1st: x
2nd: x+1
3rd: x+2
4th: x+3
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EQUATION:
2(x+2 + x+3) = 3x + 91
4x + 12 = 3x + 91
x = 79
x+1 = 80
etc.
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4) Find a set of four consecutive positive integers such that the greatest integer in the set is twice the least integer in the
I'll leave this to you.</span>
Answer:
It is because a rectangle has 4 congruent sides.
A rectangle has 4 congruent sides since it has four 90 degrees sides, its corners. This someone say a shape with 3 congruent sides is a rectangle.
This is why it is wrong.
Answer:
(
−
5
)
(
−
4
)
Step-by-step explanation:
Not 100 percent sure
Answer:
no idea- I would say the answer is 4 but i don't know if the triangles are similar or not
Step-by-step explanation:
X²/9 + y²/16 = 1
The general for mula of an ellipse is:
(x-h)²/a² + (y-k)²/b² = 1. Since h = k = 0, this ellipse
x²/9 + y²/16 = 1
passes by the center O. (Note that a = 3 and b = 4)
Moreover sin b>a so the majore axis is (on the y-axis) and a the minor axis (on the x-axis) [Its shape is as a vertical egg].
On a system of perpendicular axis that intercept in O., take on the x-axis 2 points A & B with respective coordinate A(3.0) and B(-3,0)
On the y-axis your report A'(0,+4) and B'(0,-4). So you have the vertex of the ellipse, then it's easy to draw it
