512
8x8=64
64x8=512
hope this helps!!
Let a and b be integers and b>a, then we can say:
(b-a)/3=5 now multiply both sides by 3
b-a=15
b=15+a
So there are infinitely many pairs of integers that satisfy the conditions given in the problem. For any value a, b will be 15 units greater.
Answer:
31-24x/2x-5
Step-by-step explanation:
multiply: (16-24x+15)/(2x-5)
calculate: (31-24x)/(2x-5)
write the division as a fraction: 31-24x/2x-5
add 4 each time
the nth term is a_n or f(n)
the next term after that is a_{n+1} or f(n+1)
so each term is 4 more than previous
basically
a_{n+1}=4+a_n or
f(n+1)=4+f(n)
same thing
