Question

If 8 cakes cost $62.40, how much would 3 cakes cost?

Answer 1

Solution:

Note that:

• 8 cakes = $62.40

This question requires the knowledge of Unitary method.

Step-1: Divide 8 both sides of the equation to obtain the cost for 1 cake.

• 8 cakes = $62.40
• => 8/8 cakes = $62.40/8
• => 1 cake = $7.8

Step-2: Multiply 3 both sides to find the cost of 3 cakes.

• 1 cake = $7.8
• => 3 cakes = $7.8 x 3
• => 3 cakes = $23.4

Answer 2

Answer:

$23.40

Step-by-step explanation:

Given,

Cost price of 8 cakes = $62.40

So,

Cost price of 1 cake = $ $\frac{62.40}{8}$

Therefore,

Cost price of 3 cakes

= $($\frac{62.40}{8}$ × 3)

• [On dividing 62.40 by 8]

= $(7.80 × 3)

• [On multiplying]

= $23.40

Hence,

The required cost of 3 cakes is $23.40 (Ans)