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Paladinen [302]
2 years ago
8

If a cylinder has a volume of 1004.8oz and is 60% full how many oz does it contain?

Mathematics
2 answers:
Alchen [17]2 years ago
7 0
The answer is 602.88 Oz. 
Just use googles calculator tbh It will give you the answer
bagirrra123 [75]2 years ago
7 0
If the container contains 1004.8 oz and its only 60% full, then you have to find 60% of 1004.8. Do this by multiplying 0.6 x 1004.8 and then that gives you 602.88. Now you know your answer is that the container contains 602.88 oz when only 60% full. Please let me know if this helps and if I gave the right answer! :)
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What the answer please!!!!!
Mariana [72]

Answer:

Step-by-step explanation:

To find y=mx+b we need to identify two points. I picked (20,45) and (50,65)

From these two points we can find the slope, m.

m=(y2-y1)/(x2-x1)

m=(65-45)/(50-20)

m=20/30=2/3 so now our line is

y=2x/3+b, we can solve for b using either point, I’ll use (20,45)

45=2(20)/3+b

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2 years ago
Find the solution to the initial value problem
Karo-lina-s [1.5K]

Answer:

y = (11x + 13)e^(-4x-4)

Step-by-step explanation:

Given y'' + 8y' + 16 = 0

The auxiliary equation to the differential equation is:

m² + 8m + 16 = 0

Factorizing this, we have

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The complimentary solution is

y_c = (C1 + C2x)e^(-4x)

Using the initial conditions

y(-1) = 2

2 = (C1 -C2) e^4

C1 - C2 = 2e^(-4).................................(1)

y'(-1) = 3

y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)

3 = -4(C1 - C2)e^4 + C2e^4

-4C1 + 5C2 = 3e^(-4)..............................(2)

Solving (1) and (2) simultaneously, we have

From (1)

C1 = 2e^(-4) + C2

Using this in (2)

-4[2e^(-4) + C2] + 5C2 = 3e^(-4)

C2 = 11e^(-4)

C1 = 2e^(-4) + 11e^(-4)

= 13e^(-4)

The general solution is now

y = [13e^(-4) + 11xe^(-4)]e^(-4x)

= (11x + 13)e^(-4x-4)

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3 years ago
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blue: 6/25- simplified= already in simplified form
red:10/25- simplified= 2/5
green:9/25- simplified= already in simplified form

so the answer to your question is 2/5.

hope this helped!!



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