question number 1 is 0.6 and 1.4 number 2 is 0.2 and 2.5 number 3 is 20.0
and 26.1 number 4 is 6.54 and cannot see number 5 is 29.15 and cannot see number 6 is 32.10 and cannot see number 7 is 20.051 and cannot see number 8 is 36.582 and cannot see number 9 is 16.570 and cannot see thank you
9. You need an exact answer. So I will give you it but I'll also give you an approximation because it might help you understand it more.
Because we know the cosine fo theta, we can evaluate the inverse cosine of -2/3 first to find theta.
= 131.81° approx.
Because 131.81° is in the second quadrant its third quadrant partner is 228.19°. Which would make the sine 0.75 approximately.
But we need an exact answer I suppose so which is this disgusting mess...
. I know it looks scary but it is basically all the steps we just did but without evaluating anything.
This can be simplified using: sin(x− y) = sinxcosy−cosxsiny
To... 
answer:
10. Okay. So because we have a point we can say that...
θ = 
sin(θ) = +sin()
11. arcsin(-0.37) = 
= -21.72°+2kπ or 201.72°+2kπ approx. where k has to be an integer
answer: idk if you want one or more solutions so I gave you them all.
12. arccos(-√3/2) = 
Remember that "k" must be an integer.
answer: 5π/6
Answer:
<em>45 possible connections</em>
<em />
Step-by-step explanation:
The general equation for finding the possible number of connections in a network is given as
where n is the number of computers on the network.
for 4 computers, we'll have
= 
= 6
for 5 computers, we'll have
= 
= 10.
therefore, for 10 computers, we will have
= 
= <em>45 possible connections</em>
Perimeter is the border around something...you add all the sides. So you you'll add 5+5=10 , 8+8=16 , and then you add 10+16=26. The answer is 26.
Okay so, togo flies 30 miles in 3/5 of an hour with the wind.togo flies 30 miles in 5/6 of an hour against the wind. his rate of speed with the wind was 30 / (3/5) = 30*5/3 = 150/3 = 50 mph.his rate of speed against the wind was 30 / (5/6) = 30*6/5 = 6*6 = 36 mph.3/5 of an hour times 50 mph = 30 miles.
5/6 of an hour times 36 mph = 30 miles.mph looks good.
going he was with the wind.
his rate of speed then was the airplane speed plus the wind speed.coming back he was against the wind.his rate of speed then was the airplane speed minus the wind speed.-----50 mph = A + W36 mph = A - W-----looks like A + W - (A - W) should equal 50 - 36.removing parentheses, equation becomesA + W - A + W = 14.
combining like terms, the equation becomes2*W = 14.dividing both sides by 2, equation becomesW = 7.if W = 7, then A can be found as follows:50 = A + 7A = 43.likewise,36 = A - 7A = 43.since the airplane speed is the same, it looks like the answer is good.solving in the original equations, we get3/5 * (43 + 7) = 303/5 * 50- = 3030 = 30good.-----5/6 * (43 - 7) = 305/6 * 36 = 3030 = 30good.
answer is W = 7 and A = 43.
