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Fiesta28 [93]
2 years ago
9

If there are 300 houseflies in the study, how many of them will live longer than 21 days?

Mathematics
1 answer:
Levart [38]2 years ago
8 0

The 48 flies of them will live longer than 21 days if there are 300 houseflies in the study.

<h3>What is a normal distribution?</h3>

It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.

We have mean u = 18 days

SD = 3 days

X = 21 days

From the formula:

Z = (X - u)/SD

Z = (21 - 18)/3 = 1

P(x<21) = 0.84134

P(x>21) = 1 - P(x<21) = 0.15866

Number of flies = 300×0.15866 = 47.59 ≈ 48 flies

Thus, the 48 flies of them will live longer than 21 days if there are 300 houseflies in the study.

Learn more about the normal distribution here:

brainly.com/question/12421652

#SPJ1

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(a) What is wrong with the following equation? x2 + x − 42 x − 6 = x + 7 (x − 6)(x + 7) ≠ x2 + x − 42 The left-hand side is not
jeka94

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Attached please find answer

Step-by-step explanation:

= (x² + x - 42) / (x - 6)

= [x² + (7x - 6x) - 42] / (x - 6)

= [x² + 7x - 6x - 42] / (x - 6)

= [(x² + 7x) - (6x + 42)] / (x - 6)

= [x(x + 7) - 6(x + 7)] / (x - 6)

= [(x + 7)(x - 6)] / (x - 6)

= x + 7 → when x approches 6

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Other method:

Lim   (x² + x - 42) / (x - 6)

x→ 6

When x → 6, there is an indeterminate expression because: 6 - 6 = 0

Do you know the l'Hôpital's rule, when x → a:

Lim [ f(x) / g(x) ] = Lim [ f'(x) / g'(x) ]

f(x) = x² + x - 42

f'(x) = 2x + 1

g(x) = x - 6

g'(x) = 1

= f'(x) / g'(x)

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Help I need this answer ASAP
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