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Blababa [14]
3 years ago
7

11 to the 8th power divided by 11 to the 3rd power

Mathematics
2 answers:
borishaifa [10]3 years ago
4 0
161051 is ur answer sir
Novosadov [1.4K]3 years ago
4 0

Answer:

11 to the 5th power, or 11^5.

Step-by-step explanation:

11^8

------ = 11^(8-3) = 11^5 (answer)

11^3

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In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s
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Answer:

a) \mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

b) From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

c) P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

P(Z\geq2.070)=1-P(Z

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

\mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

Part c

For this case we want this probability:

P(\bar X \geq 285)

And we can use the z score defined as:

z=\frac{\bar x -\mu}{\sigma_{\bar x}}

And using this we got:

P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

And using a calculator, excel or the normal standard table we have that:

P(Z\geq2.070)=1-P(Z

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Answer:

The number of candidates is 136.

Step-by-step explanation:

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Answer:

<u><em>canvases over weeks </em></u>

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<u><em>Now we have c(w(h)), this means first we apply w(h) which will give us hours per week and then we'll apply function 'c' on the results of 'w' (that is number of hours for weeks painted). As result we'll get number of canvas </em></u>per week!

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