Hi there! :)
Answer:
---- Starting with: ----
x² - 10x + 24
Since we have a leading coefficient of 1, simply find two numbers that sum up to -10 and multiply into 24.
By guessing and checking, we get the numbers -6 and -4. Put these into factors:
(x - 6)(x - 4)
Therefore, a binomial present in factored form is D. x - 4
Hello macelynn190!
To solve this question we need to substitute the given values of 'a' & 'b' in the equation & then simplify it.
Given,
Now, substitute this in the place of 'a' & 'b'..
Lastly, simplify it...
- The answer is <u>-</u><u>9</u><u>/</u><u>2</u><u> </u><u>or </u><u>-</u><u>4</u><u>.</u><u>5</u>
__________________
Hope it'll help you!
ℓu¢αzz ッ
Step-by-step explanation:
Let's represent the two integers with the variables and .
From the problem statement, we can create the following two equations:
With the first equation, we can subtract from both sides to isolate the variable to the left-hand side:
Now that we have a value for , we can plug it into the second equation and solve for :
Now, let's move everything to one side of the equation:
Factoring this quadratic will give us two values for :
Since we now know , we can plug this back into either of the original equations to get a value for , which will be .
So the two numbers that sum to and have a product of are .
We need to figure out how many more cans they need to bring. We figure this out by subtracting 403 from 1,000, which gives us 596 more cans. We now divide 596/28, to find how many each student would need to bring. This equals 21.3. You might want to mention that each student can't bring .3 of a can, so the answer could be 22 also.
Answer:
The diameter decreases at a rate of 0.053 cm/min.
Step-by-step explanation:
Surface area of an snowball
The surface area of an snowball has the following equation:
In which d is the diameter.
Implicit differentiation:
To solve this question, we differentiate the equation for the surface area implictly, in function of t. So
Surface area decreases at a rate of 3 cm2/min
This means that
Tind the rate (in cm/min) at which the diameter decreases when the diameter is 9 cm.
This is when . So
The diameter decreases at a rate of 0.053 cm/min.