In order to calculate the energy required, we must first know the specific heat capacity, or the amount of energy required to raise the temperature of a unit mass of substance by 1 degree Celsius, of water. This, at 1 atm pressure, is 4.18 joules per gram.
Next, we use the formula:
Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity and ΔT is the change in temperature.
Q = 435 * 4.18 * (100 - 25)
Q = 136.4 kJ
Answer: apple falling
Explanation: apple is at rest until a force (gravity) acts upon it
PV=nRT
So
NRT/P=V ...
SI units for pressure is pascals so 81.8KPA = 81.8 x 10^3 PA
SI units for temperature is kelvin so 15 degrees celsius = 15 +273 = 288K
(0.582 x 8.314 x 288)/81.8 x 10^3 = 0.017 m3 (cubic meters)
Answer:
W = 278.64375 Joules
Explanation:
The information given in this problem are;
Initial volume = 0L
Final volume = 2.50L
ΔV = 2.50 - 0 = 2.50 L
External pressure, P = 1.10 atm
Work = ?
These parameters are related by the equation;
w = - P ΔV
W = - (1.10 )(2.50)
W = 2.75 L atm
Upon conversion to joules;
1 liter atmosphere is equal to 101.325 joule
W = 278.64375 Joules