H2*1.01=2.02
S1*32.06=32.06
O 4*16.00=64.00
2.02+32.06+64.00=98.08
final answer is 98.08
Answer:
Explanation:
We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.
M_r: 84.01
H₂SO4 + 2NaHCO₃ ⟶ Na₂SO₄ + 2CO₂ + 2H₂O
n/mol: 6
1. Use the molar ratio of NaHCO₃ to calculate the moles of NaHCO₃.
2. Use the molar mass of NaHCO₃ to calculate the mass of NaHCO₃.
You must use of NaHCO₃.
Answer:
0.0000098 should be the answer
Explanation:
Molar mass=MM
MM(Hg)=200.59g/mol
MM(N)=14.01g/mol
MM(O)=16.00g/mol
MM(Hg(NO3)2)=MM(Hg)+2*MM(N)+6*MM(O)=200.59g+2*14.01g+6*16g=324.61g/mol
1.60mol Hg(NO3)2*(324.61g/mol)=519.376 g=519 g Hg(NO3)2