Question

Se disuelven 10 g de acido carbónico H2CO3 en 150 g de agua. Determina la concentración % m/m de esa disolución?

Answer 1

The question is: 10 g of carbonic acid H2CO3 are dissolved in 150 g of water. Determine the% m / m concentration of that solution?

Answer: The% m / m concentration of that solution is 6.66%.

Explanation:

Given: Mass of solute = 10 g

Mass of solvent = 150 g

Formula used to calculate the %m/m is as follows.

$Percent (m/m) = \frac{mass of solute}{mass of solvent} \times 100$

Substitute the values into above formula as follows.

$Percent (m/m) = \frac{mass of solute}{mass of solvent} \times 100\\= \frac{10 g}{150 g} \times 100\\= 6.66%$

Thus, we can conclude that the% m / m concentration of that solution is 6.66%.