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4 years ago

How do I solve this problem? Can someone please help?

Physics

1 answer:

babymother [125]4 years ago

4 0

Which were difficulties that the builders of the transcontinental railroad found ways to overcome? Select all the choices that apply.

Answer: Out of all the options presented above the ones that represent the difficulties that the builders of the transcontinental railroad found ways to overcome are answer choices A) providing supplies to build the tracks and support the workers and B) natural barriers such as mountains, rivers, and forests. It was also the same reason why the transcontinental railroad was being constructed. It would help the transportation of if this is hitory i dont know what subject this is but if its history heres the answers

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You started to run at 10 km/h when you left your house and you arrived at school 30 minutes later. Assuming that your average ac

yarga [219]

Answer:

25km/h

Explanation:

this question involves the application of the first equation of motion

v=u+at

Where v= final velocity

u=initial velocity

a = acceleration

t= time

v=? u=10km/h t=30mins =0.5h (half an hour) a=30km/h/h

therefore, v= 10 + (30 ×0.5)

v=10 +15

v=25km/h

note that time was converted to h so that the units in the question would be uniform

4 0

3 years ago

What process of the hydrological cycle is maintained by the ocean’s large surface area ?

riadik2000 [5.3K]

Evaporation is the process of the hydrological cycle maintained by the ocean's large surface area.

7 0

3 years ago

Two wires are identical, except that one is aluminum and one is tungsten. the aluminum wire has a resistance of 0.22 ω. what is

Margaret [11]

The resistance R of a piece of wire is given by
$R=\rho \frac{L}{A}$
where $\rho$ is the resistivity of the material, L is the length of the wire and A is its cross-sectional area.

Using this formula, and labeling with A the aluminum and with T the tungsten wire, we can write the ratio between $R_T$ (the resistance of the tungsten wire) and $R_A$ (the resistance of the aluminum wire):
$\frac{R_T}{R_A}= \frac{\rho_T \frac{L}{A} }{\rho_A \frac{L}{A} }$

the two wires are identical, so L and A are the same for the two wires and simplify in the ratio, and we get:
$R_T = \frac{\rho_T}{\rho_A} R_A$

By using the resistivity of the aluminum: $\rho_A=2.65 \cdot 10^{-8} \Omega m$ and the resistivity of the tungsten: $\rho_T = 5.6 \cdot 10^{-8} \Omega m$ m we can get the resistance of the tungsten wire:
$R_T = \frac{\rho_T}{\rho_A} R_A = \frac{ 5.6 \cdot 10^{-8} \Omega m}{2.65 \cdot 10^{-8} \Omega m} (0.22 \Omega) = 0.46 \Omega$

5 0

3 years ago

¿Cómo se transforma la energía por eso uso de sistemas amortiguados en una bicicleta?

Goryan [66]

Answer:

No cheating: you’re starring in a movie w/ the last person saved in your camera roll and the last song you listened to is the title.

"let's go everywhere" the movie with taemin and taeyong sounds like something i would watch ♡ https://t.co/tGdUt7CKPc

8 0

3 years ago

The radius of curvature of a highway exit is r = 93.5 m. The surface of the exit road is horizontal, not banked. (See figure.)

trapecia [35]

Static friction keeps the car from skidding off the road and points toward the center of the curve. By Newton's second law, the car experiences

• net vertical force

F [normal] - F [weight] = 0

• net horizontal force

F [friction] = ma = mv²/r

where v is the tangential speed of the car.

It follows that

F [normal] = F [weight] = mg

and when static friction is maximized at the car's maximum speed,

F [friction] = µ F[normal] = 0.402 mg

Solve for v :

0.402 mg = mv²/r ⇒ v = √(0.402 g (93.5 m)) ≈ 19.2 m/s

8 0

3 years ago