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2 years ago

Materials that regulate the flow of current through them

Physics

1 answer:

4vir4ik [10]2 years ago

3 0

Answer:

electromagnet

Explanation:

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Infer the effect of deforestation on the carrying capacity of the Amazon rainforest.

RUDIKE [14]

Answer:

More than 20% of the amazon has been destroyed, affects biodiversity.

Explanation:

The biggest issues that the amazon is facing is the deforestation and it involves the clearing of land areas for logging, farming, and other land-use changes.

Effects that are seen are droughts, floods, destruction of habitats of flora and fauna along with the valuable services of the ecosystem.

This leads to a decrease in the carrying capacity of the species and the decline of the essential resources that are necessary to survive.

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3 years ago

A railroad car of mass 2,000 kg traveling at a velocity v = 10 m/s is stopped at the end of the tracks by a spring-damper system

Murrr4er [49]

Stopped at the end of the tracks by a spg-damper system, as shown in fig. 1

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2 years ago

A bicyclist moves at a constant speed of 6 m/s. How long it will take for the point bicyclist to move 36 m?

Rudik [331]

Answer:

6 seconds

Explanation:

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3 years ago

Read 2 more answers

A bowling ball encounters a 0.760 m vertical rise on the way back to the ball rack. Ignore frictional losses and assume the mass

Gre4nikov [31]

To solve this exercise we need the concept of Kinetic Energy and its respective change: Initial and final kinetic energy.

Let's start considering that the angular velocity is given by,

$\omega = \frac{v}{R}$

Where,

V = linear speed

R = the radius

In the case of the initial kinetic energy:

$KE_i=\frac{1}{2} mv^2 + \frac{1}{2}I \omega^2$

Where I is the moment of inertia previously defined.

$KE_i = \frac{1}{2}(m)3.5^2 + \frac{1}{2}* (\frac{2}{5} m R^2) (\frac{3.5}{R})^2$

In the case of the final kinetic energy, we have to,

$KE_f= mgh+ \frac{1}{2} mv^2 + \frac{1}{2} I \omega^2$

$KE_f = m * 9.81 * 0.76 + \frac{1}{2} m v^2 + \frac{1}{2} (\frac{2}{5} m R^2) (\frac{v}{R})^2$

For conservation of Energy we have, that

$KE_f = KE_i$ , then (canceling the mass and the radius)

$\frac{1}{2} 3.5^2 + \frac{1}{2}(\frac{2}{5})(3.5)^2= 9.81 * 0.76 + \frac{1}{2} v^2 + \frac{1}{2} (\frac{2}{5}) (v)^2$

$8.575= 7.4556+ \frac{1}{2} v^2 + \frac{1}{2} (\frac{2}{5}) (v)^2$

$1.1194= \frac{1}{2}( v^2 + (\frac{2}{5}) (v)^2)$

$2.2388= (\frac{7}{5}) (v)^2$

$v=1.26m/s$

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3 years ago

An Olympic diver is on a diving platform 3.80 m above the water. To start her dive, she runs off of the platform with a speed of

AVprozaik [17]

Answer:

the diver's speed just before she enters the water is 8.718 m/s.

Explanation:

Given;

height of the diving platform, h = 3.8 m

initial velocity of the diver, u = 1.24 m/s

the diver's speed just before she enters the water is her final velocity, = v

Apply the following kinematic equation to determine the final velocity of the girl;

v² = u² + 2gh

v² = (1.24)² + 2(9.8 x 3.8)

v² = 76.018

v = √76.018

v = 8.718 m/s

Therefore, the diver's speed just before she enters the water is 8.718 m/s.

3 0

2 years ago

*Materials that regulate the flow of current through them *

Materials that regulate the flow of current through them