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kodGreya [7K]
3 years ago
13

A solid cylinder of mass 7 kg and radius 0.9 m starts from rest at the top of a 20º incline. It is released and rolls without sl

ipping to the bottom of the incline. Assume g = 9.81 m/s2. If the difference in height between the top of the incline and the bottom is 2.3 m, the total energy of the cylinder at the bottom is:
Physics
1 answer:
ohaa [14]3 years ago
7 0

Answer:

157.8 J

Explanation:

m = mass of the cylinder = 7 kg

h = height difference in top and bottom of the incline = 2.3 m

g = acceleration due to gravity = 9.8 m/s²

TE = Total Energy at the bottom

PE = Gravitational potential energy at the top

Using conservation of energy

Total Energy at the bottom = Gravitational potential energy at the top  

TE = PE

TE = m g h

TE = (7) (9.8) (2.3)

TE = 157.8 J

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katen-ka-za [31]

Answer:

k. e. = 1/2 mv^2

1/2 * 1000 * (5)^2

1/2 * 1000 * 25

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k. e. = 1/2 mv^2

1/2 * 1000 * (10)^2

1/2 * 1000 * 100

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change in k. e. = final - initial

50000 - 12500

= 37500 joules

hope it helps you

3 0
3 years ago
Can somebody explain it to me please?​
Volgvan

Answer:

45°.

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6 0
3 years ago
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Three small objects are arranged along a uniform rod of mass m and length L. one of mass m at the left end, one of mass m at the
yKpoI14uk [10]

Answer:

See answer below

Explanation:

Hi there,

To get started, recall the Center of Mass formula for two masses:

x_c_m = \frac{m_1x_1+m_2x_2}{m_1+m_2}  where m is mass and x is displacement <em>from the center of the shape.</em>

Since masses at the center of a geometric shape have a displacement (x) value of 0, as the mass is already of the center, and does not affect Xcm. So, we can disregard the central mass, hence we use the above formula for two masses.

We can arbitrarily define left to be a negative (-) displacement, and vice versa for right direction. We proceed with the formula:x_c_m=\frac{(-L/2)m+(L/2)2m}{m+2m} =\frac{(L/2)(-m+2m)}{3m} \\ x_c_m=\frac{L(m)}{6m} =\frac{L}{6}

Since we defined left (-) and right (+), we notice the center of mass is (+) value. This makes sense, as there is slightly more mass on the right side. Hence, you should place a support 1/6 of the rod's length away from the rod's center.

Study well and persevere.

thanks,

4 0
4 years ago
If a spring stores 5 J of energy when it's compressed by .5 m, what is the spring constant of the spring?
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=40N/m
4 0
4 years ago
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