Answer:
k. e. = 1/2 mv^2
1/2 * 1000 * (5)^2
1/2 * 1000 * 25
12500 joules
k. e. = 1/2 mv^2
1/2 * 1000 * (10)^2
1/2 * 1000 * 100
50000
change in k. e. = final - initial
50000 - 12500
= 37500 joules
hope it helps you
Answer:
45°.
It is a property of the parabolas.. When the angle between a parabola and the x-axis is 45° the range is maximum.
Cesium has the least ionization energy and can donate electrons very easily !
Answer:
See answer below
Explanation:
Hi there,
To get started, recall the Center of Mass formula for two masses:
where m is mass and x is displacement <em>from the center of the shape.</em>
Since masses at the center of a geometric shape have a displacement (x) value of 0, as the mass is already of the center, and does not affect Xcm. So, we can disregard the central mass, hence we use the above formula for two masses.
We can arbitrarily define left to be a negative (-) displacement, and vice versa for right direction. We proceed with the formula:
Since we defined left (-) and right (+), we notice the center of mass is (+) value. This makes sense, as there is slightly more mass on the right side. Hence, you should place a support 1/6 of the rod's length away from the rod's center.
Study well and persevere.
thanks,
EPE= 0.5 * spring constant * (extension)^2
Spring constant=EPE/0.5*extension^2
5J/0.5*0.5^2
=40N/m