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marusya05 [52]
3 years ago
6

Solve the equation 9b2 + 30b + 25 =0

Mathematics
2 answers:
weqwewe [10]3 years ago
5 0

Answer:

C. b = -5/3

Step-by-step explanation:

9b2 + 30b + 25 =0

(3b)^2 + 30b +(5)^2  = 0  <---perfect square

(3b + 5)^2 = 0

(3b + 5) = 0

3b = -5

 b = -5/3

Answer

C. b = -5/3

Daniel [21]3 years ago
5 0

Answer:

C. b = -5/3

Step-by-step explanation:

9b² + 30b + 25 = 0

We can factor: two numbers that add up to 30 and its' product is 225: <em>15 & 15</em>.

So we have <em>9b² + 15b + 15b + 25 = 0</em>.

We can change this to <em>(3b + 5) (3b + 5), </em>or <em>(3b + 5)²</em>.

This means there is only one solution: <em>3b + 5 = 0</em>.

This can be turned into <em>3b = -5</em> -> b = -5/3.

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