<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
1angle = 90
4 angles =360
the answer is false
Note:
0.13 x 16500 = 2145
16500 - 2145 = 14355 for the first year.
Continue this for 7 more years to get your answer.
Polygons are closed figures so any figure that is not closed is not a polygon
This is expression is not equal because the left hand and right hand side are different
