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2 years ago

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Mathematics

1 answer:

ICE Princess25 [194]2 years ago

7 0

The amount of gas that would be left after 2 hours is 10.50 gallons

The amount of gas that would be left after t hours is 13 - 1.25t gallons

<h3>Calculating amount</h3>

From the question, we are to determine how much gas would be left after driving for 2 hours

From the given information,

Aria currently has 13 gallons of gas in her car

and

Each hour that she drives, her car uses up 1.25 gallons of gas.

Thus,

After 2 hours, her car would have used 2 × 1.25 gallons of gas

2 × 1.25 = 2.50 gallons of gas

Therefore,

The amount of gas that would be left after 2 hours = 13 gallons - 2.50 gallons

The amount of gas that would be left after 2 hours = 10.50 gallons

For the amount of gas that would be left after t hours
Since the car uses 1.25 gallons of gas per hour

Then,

The amount of gas that would be left after t hours = 13 - 1.25 × t

The amount of gas that would be left after t hours = 13 - 1.25t gallons

Hence,

The amount of gas that would be left after 2 hours is 10.50 gallons

The amount of gas that would be left after t hours is 13 - 1.25t gallons

Learn more on Calculating Amount here: brainly.com/question/26296201

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Answer:

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No she can't make to the airport.

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Given the cab charges $0.8 per mile and $2 for tolls.

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The total charge is $ $(0.8*x+2)$

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$x\leq \frac{14}{0.8}$

$x\leq 17.5$

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Answer:

(a) $\frac{5}{7},\frac{1}{6}$ (b) $\frac{1}{7},\frac{1}{6}$ (c) $\frac{5}{7},\frac{2}{3},\frac{3}{5}$

Step-by-step explanation:

GIVEN: Miranda has a bag of marbles with $5$ blue marbles, $1$ white marbles, and

TO FIND: a) A Blue, then a red Preview

,b)A red, then a white Preview

,c) A Blue, then a Blue, then a Blue.

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Total marbles in bag $=7$

(a)

Probability of drawing blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{5}{7}$

As marble is not returned to bag,

Probability of drawing red marble $=\frac{\text{total red marble}}{\text{total marbles}}$

$=\frac{1}{6}$

(b)

Probability of drawing red marble $=\frac{\text{total red marble}}{\text{total marbles}}$

$=\frac{1}{7}$

As marble is not returned to bag,

Probability of drawing white marble $=\frac{\text{total white marble}}{\text{total marbles}}$

$=\frac{1}{6}$

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Probability of drawing second blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

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As marble is not returned to the bag

Probability of drawing third blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

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