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3 years ago

Choose the expressions below that are equivalent to the following algebraic expression.

Mathematics

2 answers:

rodikova [14]3 years ago

7 0

Answer

Step-by-step explanation:

Ymorist [56]3 years ago

4 0

Answer:

10x -6 +4x & -6 + 14x are equivalent to the algebraic Expression : 2(5x -3) + 4x

Step-by-step explanation:

First, you should Simplify the expression.

2(5x -3) + 4x = 10x -6 +4x <-- Here we distributed. We see this expression is an option, so you would choose that.

We Contiue:

10x -6 + 4x = -6 + 14x <-- here we added the like terms, 10x and 4 x

-6x + 14 = -2.3. <-- here we got our answer, but our choices are only expressions, so this is just an extra step.

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Answer:

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Step-by-step explanation:

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4 years ago

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Answer:

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3 years ago

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3 years ago

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Answer:

Hence, the relation R is a reflexive, symmetric and transitive relation.

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$R=\{l_1,l_2\in A|l_1 \;\text{is parallel to}\; l_2\}$

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Which type of relation R on set A.

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A relation R on a set A is called reflexive relation if every $a\in A$ then $(a,a)\in R$ .

So, the relation R is a reflexive relation because a line always parallels to itself.

A relation R on a set A is called Symmetric relation if $(a,b)\in R$ then $(b,a)\in R$ for all $a,b\in A$ .

So, the relation R is a symmetric relation because if a line $l_1$ is parallel to the line $l_2$ the always the line $l_2$ is parallel to the line $l_1$ .

A relation R on a set A is called transitive relation if $(a,b)\in R$ and $(b,c)\in R$ then $(a,c)\in R$ for all $a,b,c\in A$ .

So, the relation R is a transitive relation because if a line $l_1$ s parallel to the line $l_2$ and the line $l_2$ is parallel to the line $l_3$ then the always line $l_1$ is parallel to the line $l_3$ .

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