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vampirchik [111]
3 years ago
5

Substance Specific Heat (cal/g°C) Specific Heat (J/g°C) water 1.00 4.18 steam 0.96 4.02 alcohol 0.59 2.47 ice 0.50 2.09 wood 0.4

1 1.72 oil (vegetable) 0.40 1.67 air 0.28 1.17 aluminum 0.22 0.92 brick 0.22 0.92 glass 0.22 0.92 sand 0.20 0.84 copper 0.09 0.38 mercury 0.03 0.13 A 16.6 g sample of alcohol absorbs 890 Joules of energy as it is heated. If the initial temperature of the alcohol was 21.5 °C, what is the final temperature of the ethanol?(A) 41.0 ºC(B) 19.5 ºC(C) 43.2 ºC
Engineering
1 answer:
Jobisdone [24]3 years ago
4 0

Answer:

C) 43,2°C

Explanation:

<em>Sensible heat</em> is the amount of thermal energy that is required to change the temperature of an object, the equation for calculating the heat change is  given by:

Q=msΔT

where:

  • Q, heat that has been absorbed or realeased by the substance [J]
  • m, mass of the substance [g]
  • s, specific heat capacity [J/g°C]
  • ΔT, changes in the substance temperature [°C]

To solve the problem, we clear ΔT of the equation and then replace our data:

Q=890 [J],

m=16,6 [g],

s=2,74 [J/g°C]

Q=msΔT.......................ΔT=Q/ms

ΔT=\frac{890 J}{16,6g*2,47\frac{J}{gC}}=21,7°C

As:

ΔT=Tfinal-Tinitial

Tfinal=ΔT+Tinitial

Tfinal=21,7+21,5=43,2°C

The final temperature of the ethanol is 43,2°C.

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Answer:

Q=hA(T_{w}-T_{inf})=16.97*0.5(27-300)=-2316.4J

Explanation:

To solve this problem we use the expression for the temperature film

T_{f}=\frac{T_{\inf}+T_{w}}{2}=\frac{300+27}{2}=163.5

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Re=\frac{uL}{v}=\frac{10\frac{m}{s}*0.5m}{16.96*10^{-6}\rfac{m^{2}}{s}}=2.94*10^{5}

Re<5*10^{5}, hence, this case if about a laminar flow.

Then, we compute the Nusselt number

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but the average heat transfer coefficient is h=2hx

h=2(8.48)=16.97W/m^{2}K

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Q=hA(T_{w}-T_{inf})=16.97*0.5(27-300)=-2316.4J

In this solution we took values for water properties of

v=16.96*10^{-6}m^{2}s

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I hope this is useful for you

regards

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2 years ago
A fluid of density 900 kg/m3 passes through a converging section of an upstream diameter of 50 mm and a downstream diameter of 2
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Answer:

Q= 4.6 × 10⁻³ m³/s

actual velocity will be equal to 8.39 m/s

Explanation:

density of fluid = 900 kg/m³

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