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Semmy [17]
3 years ago
10

3. Suppose that a class named Bicycle contains a private nonstatic integer named height, a public nonstatic String named model,

and a public static integer named wheels. Which of the following are legal statements in a class named BicycleDemo that has instantiated an object as Bicycle myBike new Bicycle C);? f. Bicycle. model Hurricane a. myBike height 26; b. my Bike model Cyclone g. Bicycle. int 3 3; c. myBike Wheels 3 d. my Bike .model 108; i. Bicycle wheels 2 e. Bicycle height 24; j. Bicycle yourBike myBike
Engineering
1 answer:
Vilka [71]3 years ago
7 0

Answer:

The solution to the given problem is provided below.

Explanation:

a.) myBike.height = 26;                                                 Not Legal statement

b.) myBike.model = “Cyclone”:                                    Legal statement

c.) myBike.wheels = 3;                                                  Legal statement

d.) myBike.model = 108;                                               Not legal statement

e.) Bicycle.height = 24;                                                  Not Legal statement

f.) Bicycle.model = “Hurricane”;                                 Not legal statement

g.) Bicycle.int = 3;                                                           Not Legal statement

h.) Bicycle.model = 108;                                                Not Legal Statement

i.) Bicycle.wheels = 2;                                                    Legal Statement

j.) Bicycle yourBike = myBike;                                      Legal Statement

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If you are interested only in the temperature range of 20° to 40°C and the ADC has a 0 to 3V input range, design a signal condit
mario62 [17]

Explanation:

Temperature range → 0 to 80'c

respective voltage output → 0.2v to 0.5v

required temperature range 20'c to 40'c

Where T = 20'c respective voltage

\begin{aligned}v_{20} &=0.2+\frac{0.5-0.8}{80} \times 20 \\&=0.2+\frac{0.3}{80} \times 20 \\V_{20} &=0.275 v\end{aligned}

\begin{aligned}\text { when } T=40^{\circ} C & \text { . } \\v_{40} &=0.2+\frac{0.5-0.2}{80} \times 40 \\&=0.35 V\end{aligned}

Therefore, Sensor output changes from 0.275v to 0.35volts for the ADC the required i/p should cover the dynamic range of ADC (ie - 0v to 3v)

so we have to design a circuit which transfers input voltage 0.275volts - 0.35v to 0 - 3v

Therefore, the formula for the circuit will be

\begin{array}{l}v_{0}=\left(v_{i n}-0.275\right) G \\\sigma=\ldots \frac{3-0}{0.35-0.275}=3 / 0.075=40 \\v_{0}=\left(v_{i n}-0.275\right) 40\end{array}

The simplest circuit will be a op-amp

NOTE: Refer the figure attached

Vs is sensor output

Vr is the reference volt, Vr = 0.275v

\begin{aligned}v_{0}=& v_{s}-v_{v}\left(1+\frac{R_{2}}{R_{1}}\right) \\\Rightarrow & \frac{1+\frac{R_{2}}{R_{1}}}{2}=40 \\& \frac{R_{2}}{R_{1}}=39 \quad \Rightarrow\end{aligned}

choose R2, R1 such that it will maintain required  ratio

The output Vo can be connected to voltage buffer if you required better isolation.

3 0
3 years ago
What is the magnitude of the charge of an electron?​
viktelen [127]

Answer:

The magnitude of the charge of an electron is −1.602×10−19C

I really sorry if it incorrect

hope you have a nice dayy!

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Nonshielded cable with a 1.5-inch diameter should have a minimum bending radius of
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Answer:

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2 years ago
Write a SELECT statement that returns the same result set as this SELECT statement. Substitute a subquery in a WHERE clause for
sergiy2304 [10]

Answer:

SELECT distinct VendorName FROM Vendors

WHERE VendorID IN (

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3 years ago
Air is pumped from a vacuum chamber until the pressure drops to 3 torr. If the air temperature at the end of the pumping process
malfutka [58]

Answer:

The final pressure is 3.16 torr

Solution:

As per the question:

The reduced pressure after drop in it, P' = 3 torr = 3\times 0.133\ kPa

At the end of pumping, temperature of air, T = 5^{\circ}C = 278 K

After the rise in the air temperature, T' = 20^{\circ}C = 293 K

Now, we know the ideal gas eqn:

PV = mRT

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where

P = Pressure

V = Volume

\rho_{a} = air\ density

R = Rydberg's constant

T = Temperature

Using eqn (1):

P = \rho_{a}RT

\rho_{a} = \frac{P}{RT}

\rho_{a} = \frac{3 times 0.133\times 10^{3}}{0.287\times 278} = 0.005 kg/m^{3}

Now, at constant volume the final pressure, P' is given by:

\frac{P}{T} = \frac{P'}{T'}

P' = \frac{P}{T}\times T'

P' = \frac{3}{278}\times 293 = 3.16 torr

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