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3 years ago

What is the most common type of suspensions system used on body over frame vehicles?

1 answer:

5 0

Well, the type of suspension to be used depends on the type of vehicle. Broadly, there are 2 types of suspension systems:-

a) Rigid Axle Suspension - Used for heavy duty vehicles. Construction is simple. Comfort is not great due to low sprung & high unsprung weight. Used in Truck’s Front and rear axle both & in Car’s Rear Suspension ( Mostly Leaf Spring rear suspension ).

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g A 12,000 m3/day treatment plant has a rectangular sedimentation basin with dimensions 12 meters wide, 3 meters deep, and 25 me

Nesterboy [21]

Answer:

The settling velocity of the particles (Vs) is greater than the overflow rate (V₀), thus the particles will settle out and will be removed.

Explanation:

Given;

volumetric flow rate of the treatment, Q₀ = 12,000 m³/day

length of the rectangular tank, L = 25 m

width of the tank, W = 12 m

height of the tank, H = 3 m

settling velocity of the particles, $V_s$ = 6 x 10⁻³ m/s

The overflow rate of the sediments are calculated as follows;

$V_o = \frac{Q_o}{A_s}$

where;

As is the surface area of the tank, m²

Q₀ is the flow rate, m³/s

As = 2LW + 2LH + 2WH

As = (2 x 25 x 12) + (2 x 25 x 3) + (2 x 12 x 3)

As = 822 m²

$Q_0 (m^3/s)= \frac{12,000 \ m^3}{day} \times \frac{1 \ day}{24 \ hr} \times \frac{1 \ hour}{60 \ \min} \times \frac{1 \ \min}{60 \ s} = \frac{12,000}{24 \times 60 \times 60} (m^3/s)= \frac{12,000}{86,400} \ m^3/s\\\\Q_o = 0.139 \ m^3/s$

The overflow rate;

$V_o = \frac{Q_0}{A_s} = \frac{0.139}{822} = 1.69 \times 10^{-4} \ m/s$

The settling velocity of the particles (Vs) is greater than the overflow rate (V₀), thus the particles will settle out and will be removed.

7 0

3 years ago

What is the most embarrassing thing that has happened to you its OK no judging

Sav [38]

Answer:

I fell infront of my crush lol

Explanation:

8 0

3 years ago

Read 2 more answers

A 1.5-m-long aluminum rod must not stretch more than 1 mm and the normal stress must not exceed 40 MPa when the rod is subjected

Pavlova-9 [17]

Answer:

the required diameter of the rod is 9.77 mm

Explanation:

Given:

Length = 1.5 m

Tension(P) = 3 kN = 3 × 10³ N

Maximum allowable stress(S) = 40 MPa = 40 × 10⁶ Pa

E = 70 GPa = 70 × 10⁹ Pa

δ = 1 mm = 1 × 10⁻³ m

The required diameter(d) = ?

a) for stress

The stress equation is given by:

$S = \frac{P}{A}$

A is the area = πd²/4 = (3.14 × d²)/4

$S = \frac{P}{(\frac{3.14*d^{2} }{4}) }$

$S = \frac{4P}{{3.14*d^{2} } }$

$3.14*S*{d^{2}} = {4P}$

${d^{2}} =\frac{4P}{3.14*S}$

$d= \sqrt{\frac{4P}{3.14*S} }$

Substituting the values, we get

$d= \sqrt{\frac{4*3*10^{3} }{3.14*40*10^{6} } }$

$d= \sqrt{\frac{12000 }{125600000 } }$

$d= \sqrt{9.55*10^{-5} }$

d = (9.77 × 10⁻³) m

d = 9.77 mm

b) for deformation

δ = (P×L) / (A×E)

A = (P×L) / (E×δ) = (3000 × 1.5) / (1 × 10⁻³ × 70 × 10⁹) = 0.000063

d² = (4 × A) / π = (0.000063 × 4) / 3.14

d² = 0.0000819

d = 9.05 × 10⁻³ m = 9.05 mm

We use the larger value of diameter = 9.77 mm

3 0

3 years ago

There are little to no benefits to supplementary field identification programs

VashaNatasha [74]

Answer:

True, supplementary field identification programs tend to limit the use of routine programs that target service delivery using routine systems.

Explanation:

When supplementary field identification programs are applied in a study, they have damaging effects to other systems and programs already in progress targeting certain/similar variables in a study group.Such programs are initiated to boost the already existing systems of programs that are in continuous application( routine basis). As a supplement , we expect more positive results in the rates per the variables included in a study.However, results has proved the opposite.For example, supplementary immunization activities applied in programs targeting demographic and health systems services reveled that such programs reduce the probability of receiving the services provided by other routine health systems conducting continuous vaccination programs to the target groups.

4 0

4 years ago

PLEASE ANSWER ASAP 20 points and brainlyyy

k0ka [10]

Answer:

top right

Explanation:

4 0

3 years ago

Read 2 more answers