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3 years ago

How do i solve 8z+3;z=z ?

Mathematics

2 answers:

kati45 [8]3 years ago

8 0

If its 8z+3z=z
add like factors
so 8z=3z=11z
11z=z

Whitepunk [10]3 years ago

4 0

8z+3z=z
First simplify and put all of the common variables together.
11z=z
10z=0
Divide by 10 on each side
z=0

Check your answer:
8(0)+3(0)=0
0=0

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2 years ago

A 51-foot wire running from the top of a tent pole to the ground makes an angle of 58° with the ground. If the length of the ten

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35.11 ft

Step-by-step explanation:

This given situation can be thought of as triangle $\triangle PQR$ where PQ is the length of pole.

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c is the side opposite to $\angle C$

$\dfrac{PR}{sinQ}=\dfrac{PQ}{sinR}\\\Rightarrow sin Q =\dfrac{PR}{PQ}\times sinR\\\Rightarrow sin Q =\dfrac{51}{44}\times sin58^\circ\\\Rightarrow \angle Q =79.41^\circ$

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$\angle P +\angle Q +\angle R =180^\circ\\\Rightarrow \angle P +58^\circ+79.41^\circ=180^\circ\\\Rightarrow \angle P = 42.59^\circ$

Let us use the Sine rule again:

$\dfrac{QR}{sinP}=\dfrac{PQ}{sinR}\\\Rightarrow QR =\dfrac{sinP}{sinR}\times PQ\\\Rightarrow QR =\dfrac{sin42.59}{sin58}\times 44\\\Rightarrow QR = 35.11\ ft$

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3 years ago

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Answer:

The area of the rectangle is 48

Step-by-step explanation:

We know that AE is 6 and ED is 8, since it forms a triangle, use the Pythagorean theorem to find AD, which is one side of the rectangle.

The Pythagorean theorem says that a^2 + b^2 = c^2.

a is AE, b is ED, and c is AD, so 6^2 + 8^2 = c^2, 36 + 64 = c^2, 100 = c^2, 10 = c, so AD is 10

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The height of the triangle is also the height of the rectangle:

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