Answer:
count_p = 0
count_n = 0
total = 0
while True:
number = int(input("Enter an integer, the input ends if it is 0: "))
if number == 0:
break
else:
total += number
if number > 0:
count_p += 1
elif number < 0:
count_n += 1
print("The number of positives is: " + str(count_p))
print("The number of negatives is: " + str(count_n))
print("The total is: " + str(total))
print("The average is: " + str(total / (count_p + count_n)))
Explanation:
Initialize the variables, count_p represens the number of positives, count_n represents the number of negatives, and total represents the total of the numbers
Create a while loop iterates until the user enters 0. If the number is not 0, then add it to the total. If the number is greater than 0, increase count_p by 1. If the number is smaller than 0, increase count_n by 1.
When the loop is done, print the count_p, count_n, total, and average
Answer: Hi im Sergeant von im here to help you in any way ma'm;)
I would think it would be the last one ( A SCANNER ) i hope this maybe the right answer if not im sorry at least i gave it a shot
Explanation:
The last one " a scanner " is the one i would choose ma'm it seems logic the the Question and seems too fit in with the rest ;)
Have a good day ma'm
Answer:
for y in range(88, 43, -4):
print(y, end=" ")
Explanation:
yw
Answer:
The answer is "a1 and a2 is an array of pointers".
Explanation:
In this question, A collection of pointers refers to an array of elements where each pointer array element points to a data array element. In the above-given statement, the two-pointer type array "a1 and a2" is declared that holds the same size "8" elements in the array, and each element points towards the array's first element of the array, therefore, both a1 and a2 are pointer arrays.
