please help find out what is b/3+17=48

2 answers:

7 0

-- Subtract 17 from each side --- b/3 = 31 --- Multiply each side by 3 --- b = 93 . Note that you don't 'move' things from one side to the other. You simply do the same thing to both sides.

Triss [41]3 years ago

5 0

To find b/3, you must move the +17 from one side of the equation to the other. To be able to do that, you must change the operation sign in front of the 17. Therefore, b/3 would be 48-17, b/3 = 31. Then, in order to find b, you must also move the /3 to the other side to be able to isolate variable b. This action also requires you to change signs. Therefore b would equal 31 multiplied by 3, b = 93.

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This robotic arm is made up of two cylinders with equal volume and two triangular prism hands. The volume of each hand is

BaLLatris [955]

Answer:

$\frac{r}{3\pi h+r}$

Step-by-step explanation:

Since the height isn't given, we assume it to be "h" (of cylinders). And the answer will be in terms of "r" and "h".

The area of 1 arm is given, so the area of 2 arms would be:

$A_{arm}=2*(\frac{1}{2}r*\frac{1}{3}r*2r)=\frac{2r^3}{3}$

Now, area of 2 cylinders would be the formula:

$A_{cyl}=2*(\pi r^2 h)=2\pi r^2 h$

So, total area is A_arm PLUS A_cyl. The fractional area the arms are would be gotten by taking expression A_arm divided by A_total.

Shown below:

$\frac{A_{arm}}{A_{total}}=\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}$

We simplify further:

$\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}\\=\frac{\frac{2r^3}{3}}{2r^2(\pi h + \frac{r}{3})}\\=\frac{r}{3(\pi h + \frac{r}{3})}\\=\frac{r}{3\pi h+r}$