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S_A_V [24]
3 years ago
9

What kind of function is being illustrated by f(x)=|2x³-3x|+5?

Mathematics
1 answer:
Dimas [21]3 years ago
5 0

Answer:

Option D: Absolute value function

Step-by-step explanation:

The absolute value of a number is the distance of the number from 0 to the left or right on the number line.

We are given the function;

f(x) = |2x³ - 3x| + 5

This function contains an absolute value symbol which is |2x³ - 3x|.

This function is thus illustrated by an an absolute value function because an absolute value function will be one that contains algebraic expressions within absolute value symbols.

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Please need help on this
Ronch [10]

Ray FM has terminal point F, so that will be the first letter of the name. The second letter of the name can be any of the points to the left of F on the line:

... D, L, M, P, K

Appropriate choices are ...

  • \overrightarrow{FP}
  • \overrightarrow{FD}
8 0
3 years ago
Y = 2 cm x = 75 grams
Nookie1986 [14]

Answer:

Step-by-step explanation:

3 0
3 years ago
Solve for x and y.<br><br> 4x-3y=16<br> -2x+4y=-2<br><br> DUE 2/7/17!
Trava [24]
\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.

<span>Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
</span>\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.
\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.
--------------------
5y = 12
\boxed{\boxed{y =  \frac{12}{5}}}\end{array}}\qquad\quad\checkmark

Let's replace the value found in the first equation:
4x-3y=16\:(I)
4x-3*( \frac{12}{5}) =16
4x -  \frac{36}{5} = 16
least common multiple (5)
\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}
20x - 36 = 80
20x = 80 + 36
20x = 116
x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark



4 0
3 years ago
Can someone help with this math problem
katrin [286]

Answer:

20 ft long; 12 ft wide

Step-by-step explanation:

Let   w = the width of the garden

Then l = w + 8

       A = lw

       A = (w + 8)w

=====

The sidewalk is 4 ft wide, so, for the big rectangle consisting of garden plus sidewalk:

Width   = w +8

Length = w + 16

   Area = (w + 8)(w + 16)

=====

The <em>difference</em> between the two areas is the area of the sidewalk (320 ft²).

(w + 8)(w + 16) - (w + 8)w = 320     Factor out w + 8

         (w+ 8)(w + 16 – w) = 320      Combine like terms

                     (w+ 8) × 16 = 320      Divide each side by 16

                             w + 8 = 20        Subtract 8 from each side

                                   w = 12 ft

                                    l = 12 + 8

                                   l = 20 ft

The garden is 20 ft long by 12 ft wide.

4 0
2 years ago
2) -4x – 6(3x + 4) = -4 + 8(1 - x)
likoan [24]

Answer:

x=-2

Step-by-step explanation:

-4x – 6(3x + 4) = -4 + 8(1 - x)

Distribute

-4x – 18x  -24 = -4 + 8 -8x

Combine like terms

-22x -24 = 4-8x

Add 22x to each side

-22x+22x -24 = 4-8x+22x

-24 =4+14x

Subtract 4 from each side

-24-4 = 4+14x-4

-28 = 14x

Divide each side by 14

-28/14 =14/14

-2 =x

5 0
3 years ago
Read 2 more answers
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