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3 years ago

What kind of function is being illustrated by f(x)=|2x³-3x|+5?

Mathematics

1 answer:

Dimas [21]3 years ago

5 0

Answer:

Option D: Absolute value function

Step-by-step explanation:

The absolute value of a number is the distance of the number from 0 to the left or right on the number line.

We are given the function;

f(x) = |2x³ - 3x| + 5

This function contains an absolute value symbol which is |2x³ - 3x|.

This function is thus illustrated by an an absolute value function because an absolute value function will be one that contains algebraic expressions within absolute value symbols.

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4 years ago

F(x) = -4x2 + 4x – 4<br> Find f(3)

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3 years ago

Solve cos x + rad 2 = -cos x for over the interval [0, 2pi ]

Kamila [148]

$cos x + \sqrt{2} = -cosx \\ \\ 2 cos x + \sqrt{2} = 0 \\ \\ cos x = -\frac{\sqrt{2}}{2}$

The cosine function is negative in 2nd and 3rd quadrants, So you know that you will have 2 solutions. One between pi/2 and pi, the other between pi and 3pi/2.

Refer to a unit circle to find that
$cos (\frac{3\pi}{4}) = -\frac{\sqrt{2}}{2} \\ \\ cos (\frac{5\pi}{4}) = -\frac{\sqrt{2}}{2}$

Final Answer:
$x = \frac{3\pi}{4}, \frac{5\pi}{4}$

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