Answer: (3, -1)
Step-by-step explanation:
y = |x-3|-1
When y=|x|, vertex is (0, 0).
Now, let's translate the graph so it becomes y = |x-3|-1.
|x| ==> |x-3| Translate the graph 3 units to the right
Vertex: (0+3, 0) ==> (3, 0)
|x-3| ==> |x-3|-1 Translate the graph 1 unit down
Vertex: (3, 0-1) ==> (3, -1)
Vertex: (3, -1)
Answer:
given us,
slope= 0
(x1y1)= (3,-3)
here
(y-y1) =m(x-x1)
or, (y+3)=0(x-3)
or (y+3)= x-3
or, x+y= -3-3
x+y= -6
Step-by-step explanation:
x+y= -6
Answer:
(f + g)(x) = 12x² + 16x + 9 ⇒ 3rd answer
Step-by-step explanation:
* Lets explain how to solve the problem
- We can add and subtract two function by adding and subtracting their
like terms
Ex: If f(x) = 2x + 3 and g(x) = 5 - 7x, then
(f + g)(x) = 2x + 3 + 5 - 7x = 8 - 5x
(f - g)(x) = 2x + 3 - (5 - 7x) = 2x + 3 - 5 + 7x = 9x - 2
* Lets solve the problem
∵ f(x) = 12x² + 7x + 2
∵ g(x) = 9x + 7
- To find (f + g)(x) add their like terms
∴ (f + g)(x) = (12x² + 7x + 2) + (9x + 7)
∵ 7x and 9x are like terms
∵ 2 and 7 are like terms
∴ (f + g)(x) = 12x² + (7x + 9x) + (2 + 7)
∴ (f + g)(x) = 12x² + 16x + 9
* (f + g)(x) = 12x² + 16x + 9
Y=-2x-5x+12
Add the variables
Y=-7x+12
There^
