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mr Goodwill [35]
3 years ago
8

What are the solutions to the system y=x^2-6x+7 y=-x+13

Mathematics
2 answers:
Burka [1]3 years ago
5 0

Answer:

The solutions are (-1, 14) and (6, 7)  

Step-by-step explanation:

Given two equations

y=x^2-6x+7.......(1)

y=-x+13...............(2)

we have to solve the above two equations

Substitute the value of y from (2) equation to (1), we get

-x+13=x^2-6x+7

x^2-5x-6=0

By middle term splitting method

x^2-6x+x-6=0

x(x-6)+1(x-6)=0

(x+1)(x-6)=0

x=-1,6

(2) ⇒  y=-x+13

when x=-1, y=-(-1)+13=1+13=14

when x=6, y=-6+13=7

Hence, the solutions are (-1, 14) and (6, 7)

dolphi86 [110]3 years ago
3 0
I've attached the graphs to this answer. I hope they help. 

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Answer:

Step-by-step explanation:

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5x+x^2 or x^2+5x

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Rudiy27
Pythagorean Theorem is

a ²+ b ² = c ²

a and b are the shorter sides, while c is the hypotenuse, or longest side. Let’s say the side we are looking for is “b”.

Let’s first rearrange the equation, then sub in.

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Find the distance between the points (1, 3) and (-7, 2).
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Select ALL of the expressions equivalent to 4(7-6x)
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When you have a negative exponent, you move the variable with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

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\frac{1}{2y^{-3}} =\frac{y^3}{2}  (you don't move the "2" because "2" has an exponent of 1, only "y" has the negative exponent)

\frac{5^{-2}}{y}=\frac{1}{(5^2)y} =\frac{1}{25y}

When you multiply a variable with an exponent by a variable with an exponent, you add the exponents together. (But you can only combine the exponents when the variables are the same)

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x^3(x^5)=x^{(3+5)}=x^8

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There's two ways you can do this. Either by first making all the exponents positive then do subtraction, or multiply them then make all the exponents positive. I'm doing the 2nd way.

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36(w^1)(u^{-1})(y^3)     Now make all the exponents positive

\frac{36wy^3}{u}

If you were to do subtraction, here is what you need to know:

When you divide a variable with an exponent by a variable with an exponent, you subtract the exponents together. (Reminder: they have to be the same variable in order to combine the exponents)

For example:

\frac{x^3}{x^2} =x^{(3-2)}=x^1   or  x

\frac{y^2}{y^4} =y^{(2-4)}=y^{-2}=\frac{1}{y^2}

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