Answer:
To find f-¹(x) of f(x) equate f(x) to y
That's
f(x) = y
So we have

Next interchange the variables that's x becomes y and y becomes x
That's

Next make y the subject
Cross multiply
We have
4y - 7 = 10x
Move -7 to the right side of the equation
4y = 10x + 7
Divide both sides by 4
We have the final answer as

So

Hope this helps you
C. 1.5 hours. divide 12 by 8, and you get 1.5.
Answer:
The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.
Step-by-step explanation:
The average speed is given by the following equation:

From 10A.M. to noon.
You traveled at 50mph during 2 hours. So how long you traveled?



You traveled 100 miles.
What was your average speed over the time interval from 9 A.M. to noon
From 9 A.M. to 10 A.M, you did not travel.
From 10 P.M. to noon, 100 miles.
So 100 miles during 3 hours.

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.
Answer:
This is late you said it was due 5 min. yet I this was posted 5 hours. No one can help now.
Step-by-step explanation: