The roots of an equation is determined at the point where its graph passes the x-axis. In other words, the roots of the function is/are its x-intercepts. From the data points, that would be (3,0). So, the answer is A.
3 is in the tens and 1 is in the ones. To explain more easily... 30+1 is 31.<span />
Answer: I'm pretty sure it's A!
You are given triangle RST with vertices R(-3,-1), S(-1,-1) and T(-4,-5).
1. Apply the rotation of 90° counterclockwise about the origin that has a rule:
(x,y)→(-y,x).
Then
- R(-3,-1)→R''(1,-3),
- S(-1,-1)→S''(1,-1),
- T(-4,-5)→T''(5,-4).
2. Second transformation is translation 1 unite up with a rule:
(x,y)→(x,y+1).
So
- R''(1,-3)→R'(1,-2);
- S''(1,-1)→S'(1,0);
- T''(5,-4)→T'(5,-3).
As you can see these points are exactly those from the task condition.
Answer: 1st transfomation is rotation of 90° counterclockwise about the origin and 2nd transformation is translation 1 unite up
Answer:
C. 15a^5b^15
Step-by-step explanation:
(3a^2b^7)(5a^3b^8)= 3*5*a^(2+3)*b^(7+8)= 15a^5b^15
