The net acceleration of the block is about -2.04m/s².
The mass of the block is 20Kg. The force applied is 50 N and the angle at which the force is applied is 25°. The coefficient of friction is 0.20.
When the block will be pulled along horizontal by applying Force fat an angle A, then there will be two components of force one along vertical fsinA and one along horizontal fcosA.
The friction will be in opposite direction,
So, we can say, the net Force F on the block is,
F = Fr - fcosA
Ma = uN -fcosA
Where,
a is the acceleration of the block,
M is the mass of the block,
N is the normal force,
f is the applied force and,
u is the coefficient of friction.
Putting all the values,
20(a) = 0.2(50)sin(25°) - 50cos(25°)
20a = 0.2(0.42)(50)-50(0.9)
20a = 4.2 - 45
20a = 40.8
a = -2.04m/s².
The net acceleration of the block is -2.04m/s².
To know more about acceleration, visit,
brainly.com/question/460763
#SPJ4