A train is going on a journey. First it travels east for 50 kilometers. Then it turns north and travels for 22
1 answer:
The train travel 20 kilometers in the southward direction to reach its original location.
Step-by-step explanation:
The given is,
First train travels east for 50 kilometers, then
Turns north and travels for 22 kilometers
It goes west for 50 kilometers
Step:1
Let, A - Distance of train travels from its starting point in Eastern direction at pq point
B - Distance train travels in northward direction at qr point
C - Distance of train travels in western direction at rs point
D - Distance of train travels in southward direction to reach its starting location at sp point
Step:2
Refer the attachment,
Distance of travel in northward direction and distance of travel in southward direction are equal.
qr = sp.............. (1) ( ∵ Eqn (1) from the Diagram)
20 km = 20 km
sp = 20 km
Result:
So, the distance of train travel to reach its original location in southward direction is 20 km.
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Answer:
1.60
Step-by-step explanation:
Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.
i.e Area =
So that,
for the inner part of the pipe,
r =
=
= 2.5 feet
Area of the inner part of the pipe =
= 3.14 x
= 19.625
Are of the inner part of the pipe is 19.63 .
Total diameter of the pipe = 5 + 0.2
= 5.2 feet
r =
= 2.6 feet
Area of the pipe =
= 3.14 x
= 21.2264
Area of the pipe is 21.23 .
Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe
= 21.2264 - 19.625
= 1.6014
The cross sectional area of the cement pipe is 1.60 .