The train travel 20 kilometers in the southward direction to reach its original location.
Step-by-step explanation:
The given is,
First train travels east for 50 kilometers, then
Turns north and travels for 22 kilometers
It goes west for 50 kilometers
Step:1
Let, A - Distance of train travels from its starting point in Eastern direction at pq point
B - Distance train travels in northward direction at qr point
C - Distance of train travels in western direction at rs point
D - Distance of train travels in southward direction to reach its starting location at sp point
Step:2
Refer the attachment,
Distance of travel in northward direction and distance of travel in southward direction are equal.
qr = sp.............. (1) ( ∵ Eqn (1) from the Diagram)
20 km = 20 km
sp = 20 km
Result:
So, the distance of train travel to reach its original location in southward direction is 20 km.
Answer:
225
Step-by-step explanation:
Using the basic components of summation ∑
∑n = n(n + 1) and ∑1 = n
Thus
∑ (2n - 1) ← for n = 1 to 15
= ∑2n - ∑1
= 2∑n - ∑1
= 2 ( n(n + 1)) - n
= n(n + 1) - n ← Evaluate for n = 15 ( the upper value )
= 15 × 16 - 15
= 240 - 15
= 225