The problem says that <span>Brandon sights a helicopter above a building that is 200 feet away at an angle of elevation of 30 degrees. So, you can calculate the height asked, by following this procedure:
</span>
Tan(α)=Opposite leg/Adjacent leg
α=30°
Opposite leg=x
Adjacent leg=200 feet
When you substitute these values into the formula above (Tan(α)=Opposite leg/Adjacent leg), you have:
Tan(α)=Opposite leg/Adjacent leg
Tan(30°)=x/200
You must clear "x":
x=200xTan(30°)
Therefore, the value of "x" is:
x=115 feet
<span>
How high above the ground the is the helicopter?
The answer is: 115 feet</span>
Answer:
n = 0
Step-by-step explanation:
1.2n + 1 = 1 - n
Add n and - 1 on both sides.
1.2n + n = 1 - 1
Combine like terms.
2.2n = 0
Divide both sides by 2.2.
n = 0
Answer:
12
Step-by-step explanation:
t/9=16/12
12t=144
t=12
Answer:
the Velocity of the plane is 100 mi/hr along the northeast direction
Step-by-step explanation:
According to the Question,
- Given That, the Initial velocity of the plane is 150 mi/hr along the east north direction and the wind is blowing at 50 mi/hr along the southwest direction
since the velocity of wind and plane is exactly opposite
- the relative velocity of the plane with respect to the wind is given by
, where 
is the velocity of plane = 150mi/hr and 
= velocity of wind = 50 mi/hr
- Therefore, Relative Velocity = 150-50 ⇒ 100mi/hr along northeast direction
Thus, the velocity of the plane is 100 mi/hr along the northeast direction
