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1 year ago

Write 3/5 as a % 60%

Mathematics

2 answers:

Mekhanik [1.2K]1 year ago

4 0

0.6 is the answer i think!

Alinara [238K]1 year ago

3 0

Answer:

(3/5)× 100

0.6 ×100= 60%

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On a trip to New York City eight people spent a total of $900 on transportation and 500 and hotel room if they share the cop cop

PIT_PIT [208]

Each person payed $175

First add the cost up:
$900 on transportation + $500 hotel room= $1400 total

8 people paying $1400 means divide 1400 by 8 to see how much one person payed.

1400/8 = 175
Each person payed $175

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2 years ago

Using the function below, evaluate f(-2). *<br> 2 points<br> f(x) = 3x? - 5x - 2

monitta

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3 years ago

One side of a triangle is 3 inches and its area is 36 inches. The corresponding side of

Elis [28]

its lonmg.answer

Step-by-step explanation:

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2 years ago

if your gross pay was $365 and your net pay was $313.90 what percent of your pay went towards deductions

tatiyna

I believe it would be 15%

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3 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

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2 years ago