Answer:
(x-8)(x+7)
Step-by-step explanation:
using quadratic formula we have
x= 
we have:
x^2-x-56=0
a= 1 b=-1 c=-56
so we have:
x=(-(-1)+-sqrt(1^1-4*(1)*(-56)))/(2*1)
x=1+-sqrt(1-4*(-56))/(2)
x=(1+-sqrt(225))/2
x=(1+-15)/2
so we have the roots:
x1=(1+15)/2 =8
x2=(1-15)/2=-7
so the answer is (x-8)(x+7)
I will give you my solution down here
3x-x=2+4
2x=6
x=3
Answer:
The answer to your question is the first option
Step-by-step explanation:
64
Process
1.- Find the prime factors of 64
64 2
32 2
16 2
8 2
4 2
2 2
1
64 = 2⁶
2.- Express 64 as a fractional exponent
64
3.- Simplify
64
64
64![^{1/4} = 2\sqrt[4]{2^{2}}](https://tex.z-dn.net/?f=%5E%7B1%2F4%7D%20%3D%202%5Csqrt%5B4%5D%7B2%5E%7B2%7D%7D)
4.- Result
64
Answer:
63
Step-by-step explanation: