So..hmm if you check the picture below, that's when it reaches the highest point
![\bf \textit{vertex of a parabola}\\ \quad \\ \begin{array}{lccclll} h=&-16t^2&+96t&+3952\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array}\qquad \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvertex%20of%20a%20parabola%7D%5C%5C%20%5Cquad%20%5C%5C%0A%0A%5Cbegin%7Barray%7D%7Blccclll%7D%0Ah%3D%26-16t%5E2%26%2B96t%26%2B3952%5C%5C%0A%26%5Cuparrow%20%26%5Cuparrow%20%26%5Cuparrow%20%5C%5C%0A%26a%26b%26c%0A%5Cend%7Barray%7D%5Cqquad%20%0A%5Cleft%28-%5Ccfrac%7B%7B%7B%20b%7D%7D%7D%7B2%7B%7B%20a%7D%7D%7D%5Cquad%20%2C%5Cquad%20%20%7B%7B%20c%7D%7D-%5Ccfrac%7B%7B%7B%20b%7D%7D%5E2%7D%7B4%7B%7B%20a%7D%7D%7D%5Cright%29)
so the rocket's maximum height was
![\bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}](https://tex.z-dn.net/?f=%5Cbf%20%7B%7B%20c%7D%7D-%5Ccfrac%7B%7B%7B%20b%7D%7D%5E2%7D%7B4%7B%7B%20a%7D%7D%7D)
and it took
![\bf -\cfrac{{{ b}}}{2{{ a}}}](https://tex.z-dn.net/?f=%5Cbf%20-%5Ccfrac%7B%7B%7B%20b%7D%7D%7D%7B2%7B%7B%20a%7D%7D%7D)
minutes to get there
now, when does it hit the ground? well, when f(x) = 0, that is,
![\bf 0=-16t^2+96t+3952](https://tex.z-dn.net/?f=%5Cbf%200%3D-16t%5E2%2B96t%2B3952)
solve for "t"
Answer:
First answer is 127 and second answer is 15
Answer:
1000
Step-by-step explanation:
you look very beautiful btw give me brainliest please ;)
Answer:
√{121×11×11}=√(11²×11²)=±11²=±121
Answer:
x=7° y=4°
Step-by-step explanation:
7x+131=180
7x=180-131=49
x=49/7=7°
11x+y+99=180
77+y+99=180
y=180-99-77
y=4°