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3 years ago

Which is not a way to transfer electric charges?

Physics

2 answers:

RUDIKE [14]3 years ago

8 0

Answer:

combustion

Explanation:

SOVA2 [1]3 years ago

4 0

Electric charge can be transferred by contact (touch a wire, get a shock), by friction (scuff on the carpet, zap your sister), and by induction (pick up bits of tissue with a charged glass rod).

But not by combustion. <em>(A)</em> You can't charge a battery by throwing it into the fire.

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A vertical spring with k=490N/m is standing on the ground. You are holding a 5.0kg block just above the spring, not quite touchi

WARRIOR [948]

Answer:

Compression in the spring, x = 0.20 m

Explanation:

Given that,

Spring constant of the spring, k = 490 N/m

Mass of the block, m = 5 kg

To find,

Compression in the spring.

Solution,

Since the block is suddenly dropped on the spring gravitational potential energy of block converts into elastic potential energy of spring. Its expression is given by :

$mgx=\dfrac{1}{2}kx^2$

Where

x is the compression in the spring

$x=\dfrac{2mg}{k}$

$x=\dfrac{2\times 5\times 9.8}{490}$

x = 0.20 m

So, the compression in the spring due to block is 0.20 meters.

5 0

3 years ago

A responder can protect himself/herself from radiation by using shielding as a response action. What materials are best for prot

Irina-Kira [14]

Answer:

Few millimeter thick aluminium, water, wood, acrylic glass or plastic.

Explanation:

The materials that are best for protection against beta particles are few millimeter thickness of aluminium, but for the high energy beta-particles radiations the low atomic mass materials such as plastic, wood, water and acrylic glass can be used.

These materials can also be used in personal protective equipment which includes all the clothing that can be worn to prevent any injury or illness due to the exposure to radiation.

3 0

3 years ago

The drawing shows two long, thin wires that carry currents in the positive z direction. Both wires are parallel to the z axis. T

erica [24]

Answer:

The magnitude of the magnetic field at the origin is $2.56\times 10^{-6}\ T$ .

Explanation:

Given :

50-A wire is in the x-z plane and is 5 m from the z axis.

Also , 40-A wire is in the y-z plane and is 4 m from the z axis.

Now , since both the wire are perpendicular to each other .

Therefore , magnetic field are also perpendicular to each other .

Magnetic field at origin due to wire 1 is :

$B_1=\dfrac{\mu_oI_1}{2\pi R_1}\\\\B_1=\dfrac{(50)\mu_o}{2\pi( 5)}\\\\B_1=\dfrac{5\mu_o}{\pi}$

Magnetic field at origin due to wire 2 is :

$B_2=\dfrac{\mu_oI_2}{2\pi R_2}\\\\B_2=\dfrac{(40)\mu_o}{2\pi( 4)}\\\\B_2=\dfrac{4\mu_o}{\pi}$

Now , therefore net magnetic field is :

$B=\sqrt{B_1^2+B_2^2}\\\\B=\sqrt{(\dfrac{5\mu_o}{\pi})^2+(\dfrac{4\mu_o}{\pi})^2}\\\\B=\dfrac{\sqrt{41}\mu_o}{\pi}$

Putting value of $\mu_o=4\pi \times 10^{-7}\ H/m$

We get ,

$B=\sqrt{41}\times 4\times 10^{-7}\\B=2.56\times 10^{-6}\ T$

Therefore, the magnitude of the magnetic field at the origin is $2.56\times 10^{-6}\ T$ .

5 0

3 years ago

Which statement best explains how weight management through exercise can be a physiological mechanism?

aleksley [76]

D. Exercise promotes self-control

7 0

4 years ago

Read 2 more answers

A strong weightless rope has a mass, m, hanging from the middle of it. The tension force on each rope is 25 N, and the rope droo

bezimeni [28]

By using Lami's theorem, Mass m = 1.75 kg approximately

Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.

By using Lami's theorem, we can get how much mass is hanging from the rope.

Let the angle between the rope = α = 180 - 40

α = 140 degrees

The angle between one of the rope and mass = β = 20 + 90

β = 110 degrees

The angle between the mass and the other rope = γ = 360 - (140 + 110)

γ = 360 - 250

γ = 110 degrees

W/ sinα = T/ sinβ = T/sinγ

W/ sinα = T/ sinβ

Substitute all the necessary parameters

W/sin140 = 25/sin 110

W / 0.643 = 25 / 0.939

W = 17.1 N

Weight W = mg

17.1 = 9.8m

mass m = 17.1/9.8

Mass m = 1.7455 kg

Mass m = 1.75 kg approximately

Therefore, 1.75 kg mass is hanging from the rope.

Learn more about resolution of forces here: brainly.com/question/1858958

4 0

3 years ago