An example would be gravity
Answer:
0.5 g
Explanation:
The half-life of a radioactive isotope is the time it takes for a certain amount of that isotope to halve.
In this case, we have an isotope of Americium-241, which has a half-life of

This means that after 1 half-life (432 years), there will be an amount of americium equal to half its initial amount.
In this problem, the initial amount of americium is

Therefore, after 432 years (1 half-life), the amount of americium left will be half:

The wind machine on an average operates for a time of about
.
Explanation:
The wind energy is the method of using the energy carried by the wind to generate the power. The wind energy is the considered as the conventional and clean source of energy.
The wind machines require the high power winds to rotate the blades of the windmill and produce power using the energy of the moving wind.
The winds blow at such high speed for a very small time during the day, the wind machine cannot be expected to work for a longer time during the whole day.
The wind energy can be obtained form a wind mill for a limited time unlike the other form of energy like thermal energy or even the solar energy. The thermal energy can be obtained at anytime due to burning of fuel whereas the solar energy can at least be obtained during the whole day time.
Thus, the wind machine on an average operates for a time of about
.
Learn More:
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Answer Details:
Grade: Middle School
Subject: Physics
Chapter: Energy
Keywords:
wind energy, conventional source, energy, thermal, solar, 3-4 hours, high speed, machine, time, operate.
Answer:
A. Add mass to the Sun.
Explanation:
A. Add mass to the Sun.
Adding mass will make to take more time for the hydrogen to run out and hence, enough temperature will be developed to fuse helium atom into other heavier elements, and eventually get hot enough to fuse the helium in their cores into carbon.
The only hypothetical solution is that we need to add Mass to the Sun.
Answer:
option (b)
Explanation:
mass of proton, mp = m
mass of deuteron, md = 2m
charge on proton, qp = q
charge on deuteron, qd = q
The magnetic force on the charged particle when it is moving is given by
F = q v B Sinθ
where, θ is the angle between the velocity and magnetic field.
Here, θ = 90°
Let v is the velocity of both the particle when they enters in the magnetic field.
The force on proton is given by
Fp = q x v x B ...... (1)
The force on deuteron is
Fd = q x v x B .... (2)
Divide equation (1) by equation (2)
Fp / Fd = 1
Thus, the ratio of force on proton to the force on deuteron is 1 : 1.
Thus, option (b) is correct.