A responder can protect himself/herself from radiation by using shielding as a response action. What materials are best for prot
1 answer:
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Answer:
Explanation:
Since, as we know, the potential difference 'ΔV' is the difference of between the Potential energy per unit charge U/qo at one point 'B' to Potential energy per unit charge at other point 'A'. It so happens when a test charge 'qo' moves from point A to B, the potential difference becomes the change of potential energy of the system, i.e.
The electrostatic force between two charged objects is given by
where
k is the Coulomb's constant
q1 is the charge of the first object
q2 is the charge of the second object
r is the separation between the two objects
In our problem:
So if we plug these numbers into the equation, we can find the electrostatic force between the two objects:
where
k is the Coulomb's constant
q1 is the charge of the first object
q2 is the charge of the second object
r is the separation between the two objects
In our problem:
So if we plug these numbers into the equation, we can find the electrostatic force between the two objects: