Answer:
Step-by-step explanation:
Step 1: Expand by distributing sum groups.
Step 2: Expand by distributing terms.
Step 3: Expand by distributing terms.
Step 4: Collect like terms.
Step 5: Simplify.
-2(8p+2)-3(2-7p)-2(4+2p)=0
mutiply the first bracket by -2
(-2)(8p)= -16p
(-2)(+2)= -4
mutiply the second bracket by -3
(-3)(2)= -6
(-3)(-7p)= 21p
mutiply the third bracket by -2
(-2)(4)= -8
(-2)(+2p)= -4p
-16p-4-6+21p-8-4p= 0
-16p+21p-4p-4-6-8= 0 ( combine like terms)
5p-4p-4-6-8= 0
p-4-6-8= 0
p-10-8= 0
p-18= 0
move -18 to the other side to get p by itself
sign changes from -18 to +18
p-18+18= 0+18
p= 0+18
Answer: p= 18
Answer:
Step-by-step explanation:
third option I believe
Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
